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mr_godi [17]
4 years ago
6

How do I find the area

Mathematics
1 answer:
Sergeu [11.5K]4 years ago
4 0

Answer:

Get the value of each side, and then multiply the value by 2, the answer will be in square units. (this answer only applies for squares)

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Step-by-step explanation:

\frac{\sqrt{x-y}}{\sqrt{x+y}-\sqrt{x-y}}-\frac{\sqrt{x-y}}{\sqrt{x+y}+\sqrt{x-y}}\\\\=\frac{\sqrt{x-y}*(\sqrt{x+y}+\sqrt{x-y})-(\sqrt{x-y})*(\sqrt{x+y}-\sqrt{x-y})}{(\sqrt{x+y}-\sqrt{x-y})*(\sqrt{x+y}+\sqrt{x-y})}\\\\=\frac{\sqrt{x-y}*(\sqrt{x+y}+\sqrt{x-y}-\sqrt{x+y}+\sqrt{x-y})}{(\sqrt{x+y})^2-(\sqrt{x-y)^{2}}}\\\\=\frac{\sqrt{x-y}*2\sqrt{x-y}}{x+y-x+y}\\\\=2*\frac{x-y}{2y}=\frac{x-y}{y}\\\\(\frac{\sqrt{x-y}}{\sqrt{x+y}-\sqrt{x-y}}-\frac{\sqrt{x-y}}{\sqrt{x+y}+\sqrt{x-y}})*y=\frac{x-y}{y}*y\\\\=x-y

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4 years ago
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