Question

The unicorns: stardust, umo, windthorn and highflyer are enjoying themselves playing in the forest. they notice 8 spiders in the tree, 5 cockroaches, 7 bees, 3 deer, 4 cows and a pair of antlers behind a bush. how many legs do all the numbered creatures amount to all together?

Answer 1

Answer:

Total 164 legs.

Step-by-step explanation:

The unicorns : stardust, umo, windthorn and highflyer are enjoying themselves playing in the forest.

They notice 8 spiders, one spider has 8 legs = 8 × 8 = 64 legs

there are 5 cockroaches, one cockroach has 6 legs = 5 × 6 = 30 legs

7 bees, one bee has 6 legs = 7 × 6 = 42 legs

3 deer, one deer has 4 legs = 3 × 4 = 12 legs

4 cows, one cow has 4 legs = 4 × 4 = 16 legs

Total legs of all the numbered creatures all together =

64 + 30 + 42 + 12 + 16 = 164 legs

Therefore, total legs are 164.

Answer 2

There are altogether $\fbox{\begin\\\ 188 \text{legs}\\\end{minispace}}$.

Further Explanation:

Given:

The number of Unicorns is $4$: Stardust, Umo, WIndthorn and Highflyer.

The number of Spiders in the tree is $5$.

The number of cockroaches is $5$.

The number of bees is $7$.

The number of deer is $3$.

The number of cows is $4$.

The number of antlers is $2$.

To calculate:

The total number of legs of all the creatures.

Calculations:

It can be seen that the number of legs of a unicorn is $4$.

Since, there are four unicorns, it means that the number of legs of unicorns $n_{1}$ can be calculated as,

$\fbox{\begin\\\ \begin{aligned}\math n_{1}&=4\times4 \\&=16\end{aligned}\\\end{minispace}}$

Also, the number of legs of a spider is $8$.

Therefore, the number of legs $n_{2}$ of eight spiders can be calculated as,

$\fbox{\begin\\\ \begin{aligned}n_{2}&= 8 \times 8 \\ n_{2}&= 64\end{aligned}\\\end{minispace}}$

Now, the number of legs of a cockroach is $6$, it means that the number of legs $n_{3}$ of five cockroaches can be calculated as,

$\fbox{\begin\\\ \begin{aligned}\math n_{3}&= 6 \times 5 \\ n_{3}&= 30\end{aligned}\\\end{minispace}}$

Also, the number of legs of a bee is $6$, therefore the number of legs $n_{4}$ of seven bees can be calculated as,

$\fbox{\begin\\\ \begin{aligned}\math n_{4}&= 6 \times 7 \\ n_{4}&= 42\end{aligned}\\\end{minispace}}$

The number of legs of a deer is $4$ which lead to the number of legs $n_{5}$ of three deers as,

$\fbox{\begin\\\ \begin{aligned}\math n_{5}&= 4\times 3 \\ n_{5}&= 12 \end{aligned}\\\end{minispace}}$

The number of legs of a cow is $4$ that means the number of legs $n_{6}$  of four cows can be calculated as,

$\fbox{\begin\\\ \begin{aligned}\math n_{6}&= 4 \times 4 \\ n_{6}&= 16 \end{aligned}\\\end{minispace}}$

Also, since it can be seen that a pair of antlers is seen, so it means that the animal seems to be two deers.

Now, a raindeer has $4$ legs, it means that the number of legs $n_{7}$ of two raindeer is,

$\fbox{\begin\\\ \begin{aligned}\math n_{7}&= 4 \times 2 \\ n_{7}&= 8 \end{aligned}\\\end{minispace}}$

Therefore, the total number of legs  can be obtained by adding the values of $n_{1}, n_{2}, n_{3} , n_{4} , n_{5}, n_{6} \ \text{and} \ n_{7}$.

$n=n_{1}+n_{2}+n_{3}+n_{4}+n_{5}+n_{6}+n_{7}\\ n=16+64+30+42+12+16+8 \\ n= 188$

Therefore, the totakl number of legs altogether are $\fbox{\begin\\\ 188 \text{legs}\\\end{minispace}}$.

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Answer details:

Grade: Juniorschool

Subject: Mathematics

Chapter: Counting

Keywords: cockroaches, multiplication, bush , cow, bees, spider, deer, counting, legs, altogether, windthorn, addition , playing, forests, stardust, umo, antlers , highfller, creatures, unicorns.