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ollegr [7]
3 years ago
8

What's 3x + 10 - x + 12

Mathematics
2 answers:
Zinaida [17]3 years ago
5 0
2x+22 is the answer.
tatyana61 [14]3 years ago
3 0
Correct! Your answer is B. 2x+22, here's why it is though: 
<span>=<span><span><span><span><span>3x</span>+10</span>+</span>−x</span>+12
</span></span><span>=<span><span><span><span>3x</span>+10</span>+<span>−x</span></span>+12 — C</span></span>ombine like terms:
<span>=<span><span>(<span><span>3x</span>+<span>−x</span></span>)</span>+<span>(<span>10+12</span>)
Answer:
</span></span></span><span>=<span>2x<span>+22

</span>Good luck with your studies, I hope this helps~!</span></span>
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What's the table plz help
Veronika [31]
If you mean what goes in the blanks, it is 5 for the first empty box and 10 for the second empty box. 
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3 years ago
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(2x+3y) + (5x+3y) = 4 +-8
Artist 52 [7]

Answer:

Step-by-step explanation:

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3 years ago
David found and factored out the GCF of the polynomial 80b4 – 32b2c3 + 48b4c. His work is below. GFC of 80, 32, and 48: 16 GCF o
BlackZzzverrR [31]

Answer: The correct statements are

The GCF of the coefficients is correct.

The variable c is not common to all terms, so a power of c should not have been factored out.

David applied the distributive property.

Step-by-step explanation:

GCF = Greatest common factor

1) GCF of coefficients : (80,32,48)

80 = 2 × 2 × 2 × 2 × 5

32 = 2 × 2 × 2 × 2 × 2

48 = 2 × 2 × 2 × 2 × 3

GCF of coefficients : (80,32,48) is 16.

2) GCF of variables :(b^4,b^2,b^4)

b^4= b × b × b × b

b^2 = b × b

b^4 =b × b × b × b

GCF of variables :(b^4,b^2,b^4) is b^2

3) GCF of c^3 and c: c is not the GCF of the polynomial. The variable c is not common to all terms, so a power of c should not have been factored out.

4) 80b^4-32b^2c^3+48b^4c

=16b^2(5b^2-2c^3+3b^2c)

David applied the distributive property.

7 0
3 years ago
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How Manu grams of oat flour does Mr.Price need to use? complete the table​
allochka39001 [22]

Answer:

225

Step-by-step explanation:

Because of 45 time 5

8 0
3 years ago
A hypothesis test is conducted at the .05 level of significance to test whether or not the population correlation is zero. If th
finlep [7]

Answer:

Th computed value of the test statistic is 3.597

Step-by-step explanation:

The null and the alternative hypothesis is as follows:

Null Hypothesis:

\mathbf{H_o:} the population correlation coefficient is equal to zero

\mathbf{H_a:} the population correlation coefficient is not equal to zero

The test statistics for Pearson correlation coefficient is thus computed as :

t =\dfrac{r \sqrt{(n-2)}} { \sqrt{(1-(r)^2)} }

where;

r = correlation coefficient = 0.60

n = sample size = 25

So;

t =\dfrac{0.60 \sqrt{(25-2)}} { \sqrt{(1-(0.60)^2)} }

t =\dfrac{0.60 \sqrt{(23)}} { \sqrt{(1-0.36} }

t =\dfrac{0.60 *4.796} {0.8}

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Comparing to a critical value of t (23 degrees of freedom two-tailed value) = 2.069

Decision Rule:

Since computed value of t is greater than the critical value of t; We reject the null hypothesis and accept the alternative hypothesis.

Conclusion:

We conclude that the population correlation coefficient significantly differs from 0 at 5% (0.05) level of significance.

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