A) 5 to be chosen among a Total : 10 Men + 8 Women
¹⁸C₅ = (18!)/(5!)(13!) = 8,568 groups of five
b) A must to have men and women. If so we have to deduct all groups of 5 that are all men and all group of 5 that are all women
Groups of 5 with only men: ¹⁰C₅ = 252
Groups of 5 with only women: ⁸C₅ = 56
So number of committees of 5 men and women mixed =
8568 - 252 - 56 = 8,260 committees
c) 3 Women and 2 Men:
⁸C₃ x ¹⁰C₂ = 2,520 groups of 3 W and 2 M
d) More women than men, it means:
3 W + 2 M OR (we have found it in c) = 2,520)
4 W + 1 M OR ⁸C₄ x ¹⁰C₁ →→→→ = 700
5 W + 0 M OR ⁸C₅ x ¹⁰C₀ →→→→ = 56
Total where W>M = 3,276 groups of 5 where women are at least 3
Image is missing, so i have attached it.
Answer:
AC = 10sin 40°
Step-by-step explanation:
From the diagram attached, using terms in trigonometric ratio, AC is the opposite side, BC is the adjacent side and AB is the hypotenuse.
Thus, since we want to find AC;
We know that in trigonometric ratios; opposite/hypotenuse = sin θ
In the diagram, θ = 40° and AB = 10
Thus,
AC/10 = sin 40°
Multiply both sides by 10 to get;
AC = 10sin 40°
Y=-3x+-1. you subtract (-4)-(-1) =3 and 1-0 and you get 1 . so the slope is 3 over 1 . and the y intercept is -1
You could draw a pie graph, I'm assuming you know how to draw one but I'll tell you anyways. draw a circle with sixty slices, like pizza. shade in 15 percent, or nine sclices. that's my favorite way to model percentages.
