Answer:
Step-by-step explanation:
0.4 out of the 0.8/ for the 3.5 it should be 1.5
Assuming you mean y = 200 - 16t^2, we have all the required information needed to solve this problem. The y-value is the height of the building and the t-value represents the number of seconds after the shoe fell off.
Since we are trying to solve <em>for t</em>, we will be using our y-value. The problem states that we landed on a building with a height of 31 feet. We can plug this into the y-value, since that is what y is defined as (the height of the building).
Now we have:
31 = 200 - 16t^2
We can solve this to find t:
-169 = -16t^2
169 = 16t^2
10.5625 = t^2
3.25, -3.25 = t
We have found two answers for t. However, the negative value is not a solution because we can not have a negative number of seconds. Thus, 3.25 is the only value of t which works for this problem.
Since t is the value we are trying to find, we have our answer. The shoe hits the building after 3.25 seconds.
The answer is (x-y)^2
hope it helps!!!!!!
the formula is
(a-b)^2
and when you expand it, it becomes
a^2-2ab+b^2
Because a line always goes past the y-intercept and x-intercept. It's not always both, it can sometimes just be the x-intercept or the y-intercept.
When a line intersects these points, for example if a line was to intersect the x-axis then y would be equal to 0, and the opposite for the y-axis. If a line was to intersect the y-axis x would be equal to 0.
Therefore by using that knowledge, and the equation of the line [ y=mx+c or y-y1=m(x-x1) ], we can find the equation of our line. Of course you would need the gradient of that line (the value "m").
