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2 years ago

If SP = Rs 380 and sales tax is 4% then the amount of sales tax is

Mathematics

1 answer:

expeople1 [14]2 years ago

7 0

Answer:

Hello! :) I hope I’m correct!!

Step-by-step explanation:

I think the answer should be 395.20

Price= 380.00

Sales tax= 4% (15.20)

The total price will be 395.20

If SP = Rs 380 and sales tax is 4% then the amount of sales tax is 395.20

Therefore the answer will be 395.20

Hope this helps!

If you have any questions, then feel free to ask them! :)

By: BrainlyAnime! ^-^

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a five inch bamboo shoot doubles in height every three days. If the equation y=ab to the x power, where x represents the number

PtichkaEL [24]

This question was once asked before so I will put it here.

The correct answer for the question that is being presented above is this one: "x = 2; a = 5; b = 3" A 5 inch tall bamboo shoot doubles in height every 3 days. If the equation y=ab^x, where x is the number of doubling periods, represents the height of the bamboo shoot.

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3 years ago

What is p if 8/p = 3/14

anzhelika [568]

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3 years ago

Answer 1-2 no links.

aleksley [76]

Answer:

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Step-by-step explanation:

Labor unions arose in the nineteenth century as increasing numbers of Americans took jobs in factories, mines, and mills in the growing industrial economy.

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2 years ago

Read 2 more answers

A ball is thrown from an initial height of 2 meters with an initial upward velocity of 9/ms . The ball's height h (in meters) af

Alecsey [184]

A ball is thrown from an initial height of 2 meters with an initial upward velocity of 9/ms

Balls height $h= 2 +9t -5t^2$

To find all values of t for which the ball's height is 3 meters

We plug in 3 for h and solve for t

$h= 2 +9t -5t^2$

$3 = 2 +9t -5t^2$

Solve for t

$0= -1+ 9t -5t^2$

$5t^2 - 9t + 1 = 0$

Solve using quadratic formula

$t= \frac{-b+- \sqrt{b^2-4ac} }{2a}$

$t= \frac{9+- \sqrt{(-9)^2-4*5*1} }{2*5}$

After simplifying this,

$t= \frac{9+\sqrt{61}}{10}$ = 0.11898

$t= \frac{9-\sqrt{61}}{10}$ = 1.68102

the values of t for which the ball's height is 3 meters= 0.12 sec , 1.68 sec

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3 years ago

Find all points on the portion of the plane x+y+z=5 in the first octant at which f(x, y, z) = xy2z2 has a maximum value.

irina1246 [14]

Lagrange multipliers:

$L(x,y,z,\lambda)=xy^2z^2+\lambda(x+y+z-5)$

$L_x=y^2z^2+\lambda=0$
$L_y=2xyz^2+\lambda=0$
$L_z=2xy^2z+\lambda=0$
$L_\lambda=x+y+z-5=0$

$\lambda=-y^2z^2=-2xyz^2=-2xy^2z$

$-y^2z^2=-2xyz^2\implies y=2x$ (if $y,z\neq0$ )

$-y^2z^2=-2xy^2z\implies z=2x$ (if $y,z\neq0$ )

$-2xyz^2=-2xy^2z\implies z=y$ (if $x,y,z\neq0$ )

In the first octant, we assume $x,y,z>0$ , so we can ignore the caveats above. Now,

$x+y+z=5\iff x+2x+2x=5x=5\implies x=1\implies y=z=2$

so that the only critical point in the region of interest is (1, 2, 2), for which we get a maximum value of $f(1,2,2)=16$ .

We also need to check the boundary of the region, i.e. the intersection of $x+y+z=5$ with the three coordinate axes. But in each case, we would end up setting at least one of the variables to 0, which would force $f(x,y,z)=0$ , so the point we found is the only extremum.

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3 years ago