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3 years ago

If x = 5, find the value of a) x2 b) (x + 3)2

Mathematics

1 answer:

PtichkaEL [24]3 years ago

3 0

Answer: a) = 10

b) = 16

Step-by-step explanation:

a) as x = 5 so putting the value of x in given equation

5 multiplied by 2 is equal to 10

b) Putting value of x in given equation

= (5 + 3) 2

According to BODMAS solve the brackets first

= 8 x 2

= 16

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3+(2+8)2ndpower ÷4×(1/2) 4th power

PIT_PIT [208]

Answer:

412

Step-by-step explanation:

You have to follow PEMDAS and solve the problem carefully.

$\frac{3+(2+8)^{2} }{4*(\frac{1}{2} )^{2} } =\frac{3+(10)^{2} }{4*(\frac{1}{2} )^{2} } = \frac{3+100}{4*(\frac{1}{2} )^{2} } = \frac{103 }{4*(\frac{1}{2} )^{2} }$

$\frac{103 }{4*(\frac{1}{2} )^{2} } = \frac{103 }{4*(\frac{1}{16})} } = \frac{103 }{\frac{1}{4} } =\\103*4\\=412$

8 0

3 years ago

(7+8)+(5+9)+4(2+5) =

Inessa [10]

Answer: 57

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

The point-slope form of the equation of a nonvertical line with slope, m, that passes through the point (x1,y1) is...?

natulia [17]

Answer:

b. y-y1 = m(x-x1)

Step-by-step explanation:

It's a matter of definition. There are perhaps a dozen useful forms of equations for a line. Each has its own name (and use). Here are some of them.

slope-intercept form: y = mx + b
point-slope form: y -y1 = m(x -x1)
two-point form: y = (y2-y1)/(x2-x1)(x -x1) +y1
intercept form: x/a +y/b = 1
standard form: ax +by = c
general form: ax +by +c = 0

Adding y1 to the point-slope form puts it in an alternate form that is useful for getting to slope-intercept form faster: y = m(x -x1) +y1. I use this when asked to write the equation of a line with given slope through a point, with the result in slope-intercept form.

3 0

3 years ago

Consider the following function. f(x) = 9 − x2/3 Find f(−27) and f(27). f(−27) = f(27) = Find all values c in (−27, 27) such tha

oksano4ka [1.4K]

I guess the function is $f(x)=9-x^{2/3}$ . Then $f(-27)=0$ and $f(27)=0$ .

The derivative is $f'(x)=-\dfrac23 x^{-1/3}$ , but there is no $c$ such that

$-\dfrac23c^{-1/3}=0$

This doesn't contradict Rolle's theorem because $f'(0)$ does not exists. In other words, $f$ is not differentiable on (-27, 27), so the conditions of Rolle's theorem are not met. (Looks like that would be the last option, or the second to last option if the last one is "Nothing can be concluded")

6 0

3 years ago

Sharon is buying candy. she buys 5 type on the menu if she splits the price equality with four friends how mich do they each pay

larisa86 [58]

Answer:

D. 0.65

Step-by-step explanation:

0.05 x 5=0.25

0.01 x 5=0.05

0.07 x 5=0.35

0.25+0.05+0.35=0.65

they all must pay 0.65 each

5 0

3 years ago