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xeze [42]
3 years ago
6

What is the image of f for a dilation with center (0,0) and a scale factor of 10

Mathematics
1 answer:
Lapatulllka [165]3 years ago
7 0
I have attached the image for this problem:
The original coordinates of F is (-3,3)
The dilation factor is 10 and the center is at the origin
We simply multiply coordinate with the dilation factor
So,
The new coordinates of F is 
(-30, 30)
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WILL MARK BRAINLIEST!!! NEED THIS ASAP!!
DiKsa [7]
Let's solve this problem step-by-step.

STEP-BY-STEP SOLUTION:

We will be using Pythagoras theorem to solve this problem. This is as this problem forms a right-angle triangle. Pythagoras theorem is the following:

a^2 + b^2 = c^2

Where c = hypotenuse of right-angle triangle

Where a and b = other two sides of right-angle triangle

To begin with, we will substitute the values from the problem into the equation. Then we will make the height of the tree the subject of the equation.

a = height of tree = ?

b = distance from the bird on the ground to the base of the tree = 8 metres

c = distance bird travelled from the ground to the top of the tree = 9 metres

a^2 + b^2 = c^2

a^2 + 8^2 = 9^2

a^2 = 9^2 - 8^2

a = square root of ( 9^2 - 8^2 )

a = square root of ( 81 - 64 )

a = square root of ( 17 )

a = 4.123...

a = 4.1 ( rounded to the nearest tenth )

FINAL ANSWER:

Therefore, the height of the tree is 4.1 metres ( rounded to the nearest tenth ).

Hope this helps! :)
Have a lovely day! <3
3 0
3 years ago
Suppose f'(7)=9 and g(7)= 5. <br> Find h'(7) where h(x) = 3f(x) + 2g(x) + 7<br><br> h'(7)=???
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Answer:

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Step-by-step explanation:

Given:

f'(7)=9 and g(7)= 5

We have to find : h'(7)

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⇔ h(x) = 3f(x) + 2g(x) + 7   ...equation (i)

Plugging the value of 'x' = 7 in equation (i) the equation can be re-framed as:

⇔ h(7) = 3f(7) + 2g(7) + 7

⇔ h(7) = 3f(7) + 2g(7) + 7

Now plugging the value of f'=(7)=9 and g(7)=5 in the above equation:

⇔ h(7) = 3(9) + 2(5) + 7

⇔ h(7)=27+10+7

⇔ h(7)=44

So the value of h=(7) = 44 .

6 0
3 years ago
A man owns 50 shares of stock worth $30 each. The corporation declared a dividend of 6% payable in stock. How many shares did he
Tasya [4]

9514 1404 393

Answer:

  53 shares

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If we assume the price remained constant, then the number of shares increased by 6%.

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The man then owned 53 shares.

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