Math 7 A Unit 4 lesson 2 Please help quick5/10-3/101/2+3/41/6+3/87/8-5/12
1 answer:
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Answer:
5091 Km/hr and 505 km/hr
Step-by-step explanation:
Speed = Distance / Time
Let the speed of first automobile be 'x' and that of the second be 'y'
Since speed of one is 10 times greater than the other. therefore;
⇒ x = 10 y
also let time for faster automobile be 'T' and time for slower auto mobile be 't'
Since first arrive one hour earlier than second, therefore;
⇒ t = T + 1
⇒ For first automobile; ; substituting for 'x' and 'T'. Therefore;
⇒
⇒ For Second automobile;
⇒
⇒
⇒ 5600 + = 560
⇒ 5600 - 560 = -
⇒ t = 1.11 hr
also ; T = 1.11 - 1 = 0.11 hr
Speed of 1st auto = 560/0.11 = 5091 km /hr
Speed of 2nd auto = 560/1.11 = 505 km/hr