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3 years ago

What is 589 times 85

Mathematics

1 answer:

babunello [35]3 years ago

8 0

Answer:

50065

Step-by-step explanation:

5x500 is 2500, 5x80 is 400, 5x9 is 45. 80x500 is 40000, 80x80 is 640, 80x9 is 720. I split them all up and when you add them it makes 50065

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According to this diagram what is tan 62

kicyunya [14]

The figure is not attached. So, I have attached it from the link- brainly.com/question/4198293

Answer:

$\tan(62)=1.875$

Step-by-step explanation:

Label the triangle ABC as shown below.

Given:

AB = 8, BC = 15, AC = 17, m∠ABC = 90°, m∠ACB = 28°, m∠BAC = 62°

The tangent of a given angle is given as the ratio of the opposite side and the adjacent side. The opposite side is the side opposite to the angle. The adjacent side is the other leg of the right angled triangle.

Here, the opposite side to angle A is BC and adjacent side is AB.

Therefore, the tan ratio of angle A is given as:

$\tan A=\frac{BC}{AB}\\\tan (62)=\frac{15}{8}=1.875$

Hence, tan 62 = 1.875.

4 0

3 years ago

Please answer anyone you can will appreciate it

Pavel [41]

Well, for the first question, the answers will be (a) 13 per row, because 13*13=169, and (b) a square, because the dimensions will be 13x13.

8 0

3 years ago

What is the value of Variable g in this equation<br><br> G^3=729

vladimir2022 [97]

Answer:

$\sqrt[3]{g } = \sqrt[3]{729}$

$g = 9$

7 0

3 years ago

Read 2 more answers

Use l'Hôpital's Rule to find the following limit. ModifyingBelow lim With x right arrow 0StartFraction 3 sine (x )minus 3 x Ove

steposvetlana [31]

Answer:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=-\frac{1}{14}$

Step-by-step explanation:

The limit is:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{0}{0}$

so, you have an indeterminate result. By using the l'Hôpital's rule you have:

$\lim_{x \to 0} \frac{a(x)}{b(x)}= \lim_{x \to 0} \frac{a'(x)}{b'(x)}$

by replacing, and applying repeatedly you obtain:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}= \lim_{x \to 0}\frac{3cosx-3}{21x^2}= \lim_{x \to 0}\frac{-3sinx}{42x}= \lim_{x \to 0}\frac{-3cosx}{42}\\\\ \lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{-3cos0}{42}=-\frac{1}{14}$

hence, the limit of the function is -1/14

8 0

3 years ago

Help me pls it’s not too much!

ankoles [38]

9,240 yards = 5.25, or 5 1/4 miles.

3 0

3 years ago