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4 years ago

12

when you ask a question, does it take however many points you chose to give the person who answered it away? or does it take tha

t many away when they answer it?

1 answer:

Montano1993 [528]4 years ago

7 0

Answer:

the long the question is the more the point

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PLEASE HELP<br><br> Identify the radius and center <br><br><br>x^2 +y^2 -6x -2y + 1 = 0

Trava [24]

Answer:

The center is the point (3,1) and the radius is 3 units

Step-by-step explanation:

we know that

The equation of a circle in standard form is equal to

$(x-h)^{2}+(y-k)^{2}=r^{2}$

we have

$x^{2}+y^{2}-6x-2y+1=0$

Convert to standard form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$(x^{2}-6x)+(y^{2}-2y)=-1$

Complete the square twice. Remember to balance the equation by adding the same constants to each side.

$(x^{2}-6x+9)+(y^{2}-2y+1)=-1+9+1$

$(x^{2}-6x+9)+(y^{2}-2y+1)=9$

Rewrite as perfect squares

$(x-3)^{2}+(y-1)^{2}=9$

The center is the point (3,1) and the radius is 3 units

4 0

4 years ago

(-7a+7b-1)-(a+8) find the difference

aalyn [17]

Answer: -8a+7b-9

Step-by-step explanation:

(-7a+7b-1)-(a+8)

-7a+7b-1-a-8 (distributive property)

-8a+7b-9 (combine like-terms)

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4 years ago

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A rectangular flower garden in Samantha back yard has 100ft around it's edge. the width of the garden is 20 feet. what is the le

Fofino [41]

30 ft.

20+20=40 These are the short sides of the flower garden. If the total is 100 ft, you need to subtract 40 ft.

100-40=60. This is the total of the other two sides of the rectangle. Hope this helps.

4 0

3 years ago

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Nataliya [291]

<h3>Need to Do :- </h3>

To simplify the given expression .

$\red{\frak{Given}}\Bigg\{ \sf \dfrac{x - 1}{ {x}^{2} - 3x + 2} + \dfrac{x - 2}{ {x}^{2} - 5x + 6 } + \dfrac{x - 5}{ {x}^{2} - 8x + 15 }$

$\rule{200}4$

$\sf\longrightarrow \small \dfrac{x - 1}{ {x}^{2} - 3x + 2} + \dfrac{x - 2}{ {x}^{2} - 5x + 6 } + \dfrac{x - 5}{ {x}^{2} - 8x + 15 } \\\\\\\sf\longrightarrow \small \dfrac{ x-1}{x^2-x -2x +2} +\dfrac{ x-2}{x^2-3x-2x+6} +\dfrac{ x -5}{x^2-5x -3x + 15 } \\\\\\\sf\longrightarrow\small \dfrac{ x -1}{ x ( x - 1) -2(x-1) } +\dfrac{ x-2}{x ( x -3) -2( x -3)} +\dfrac{ x -5}{ x(x-5) -3( x -5) } \\\\\\\sf\longrightarrow \small \dfrac{ x -1}{ ( x-2) (x-1) } +\dfrac{ x-2}{( x -2)(x-3) } +\dfrac{ x -5}{ (x-3)(x-5) } \\\\\\\sf\longrightarrow\small \dfrac{ 1}{ x-2} +\dfrac{ 1}{ x -3} +\dfrac{1}{ x -3} \\\\\\\sf\longrightarrow \small \dfrac{1}{x-2} +\dfrac{2}{x-3} \\\\\\\sf\longrightarrow \small \dfrac{ x-3 +2(x-2)}{ ( x -3)(x-2) } \\\\\\\sf\longrightarrow \small \dfrac{ x - 3 +2x -4 }{ (x-3)(x-2) } \\\\\\\sf\longrightarrow \underset{\blue{\sf Required \ Answer }}{\underbrace{\boxed{\pink{\frak{ \dfrac{ 3x -7}{ ( x -2)(x-3) } }}}}}$

$\rule{200}4$

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3 years ago

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I'll give you brainlyest if you tell me the answer. Just for fun!

Leno4ka [110]

Answer:

7

Step-by-step explanation:

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4 years ago

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