The probability of winning exactly 21 times is 0.14 when the probability of winning the arcade game is 0.659.
We know that binomial probability is given by:
Probability (P) = ⁿCₓ (probability of 1st)ˣ x (1 - probability of 1st)ⁿ⁻ˣ
We are given that:
Probability of winning on an arcade game = P(A) = 0.659
So, the Probability of loosing on an arcade game will be = P'(A) = 1 - 0.659 = 0.341
Number of times the game is being played = 30
We have to find the Probability of winning exactly 21 times.
Here,
n = 30
x = 21
P(A) = 0.659
P'(A) = 0.341
Using the binomial probability formula, we get that:
Probability of winning exactly 21 times :
P(21 times) = ³⁰C₂₁ (0.659)²¹ x (0.341)⁷
P( 21 times ) = 0.14
Therefore, the probability of winning exactly 21 times is 0.14
Learn more about " Binomial Probability " here: brainly.com/question/12474772
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Answer:
Three 1.5-pound jars of honey for $13.05
Step-by-step explanation:
15.35/5 = 3.07
3x1.5=4.5
13.05/4.5 = 2.90
Answer:
1/392 cubic yard
Step-by-step explanation:
V = Bh = (1/28 yd²)·(1/14 yd) = 1/(28·14) yd³ = 1/392 yd³
Because they do not have like bases.
First you have to remember that to find a percentage you can multiply a number by the percentage's decimal form, for example 40% of 100 would be .40 * 100.
Anyways, 24*.40 =9.6.
To find the percentage however, you must divide 24/40 which equals 0.6, which is equal to the percentage 60%.
To find the third question, you must multiply 24 by 2.5 (0.4 * 2.5 = 1) and you should get 60.
The last question you may have made a typo on, you repeated the first question.
