36450
Step-by-step explanation:
6(9)(3(9) -2)
54(27-2)
1458(25)
36450
Let L and S represent the weights of large and small boxes, respectively. The problem statement gives rise to two equations:
.. 7L +9S = 273
.. 5L +3S = 141
You can solve these equations various ways. Using "elimination", we can multiply the second equation by 3 and subtract the first equation.
.. 3(5L +3S) -(7L +9S) = 3(141) -(273)
.. 8L = 150
.. L = 150/8 = 18.75
Then we can substitute into either equation to find S. Let's use the second one.
.. 5*18.75 +3S = 141
.. S = (141 -93.75)/3 = 15.75
A large box weighs 18.75 kg; a small box weighs 15.75 kg.
Answer:
Step-by-step explanation:
Subtract 6 from 18. 3x=18. You could divide by 3 to get x=6
Step-by-step explanation:
If you use synthetic division, you get,
Which is,
Answered by GAUTHMATH
Answer:
It is given Kendrick’s kennel has 2 spots for cats for every 7 spots for dogs.
Step-by-step explanation:
Let Kendrick'a kennel has 2x spots for cats .
So Kendrick will have 7x spots for dogs.
Total number of spots for cats and dogs = 2x+7x=9x.
If he has total of 144 spots for both cats and dogs then .
9x=144
Dividing both sides by 9
x=16.
Number of spots for cats= 2x=2(16)=32
Number of spots for dogs = 7x=7(16)=112.
Number of spots dogs have more than sats = 112-32=80
Kendrick kennel has 80 more spots for dogs than cats .
