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4 years ago

6

Can someone give me the right answer for this. need it ASAP.

2 answers:

vesna_86 [32]4 years ago

8 0

Answer: Carl<Julie<Bruno

Step-by-step explanation:

Carl has the least, Julie is in second, And bruno has the most

Hope this Helps!!:D

Tems11 [23]4 years ago

7 0

Answer:

Carl then Bruno and then Julie

Step-by-step explanation:

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Use linear approximation, i.e. the tangent line, to approximate √ 16.2 as follows: Let f ( x ) = √ x . Find the equation of the

Dvinal [7]

The linear approximation to $f(x)$ near $x=16$ is

$L(x)=f(16)+f'(16)(x-16)$

We have

$f(x)=\sqrt x\implies f(16)=4$

$f'(x)=\dfrac1{2\sqrt x}\implies f'(16)=\dfrac18$

$\implies L(x)=4+\dfrac18(x-16)=\dfrac x8+2$

Then

$f(16.2)\approx L(16.2)\iff\sqrt{16.2}\approx\dfrac{16.2}8+2$

$\implies\boxed{\sqrt{16.2}\approx4.025=\dfrac{161}{40}}$

5 0

3 years ago

What is the effect on the graph of the function f(x) = x2 when f(x) is changed to f(x − 6)?

suter [353]

Answer:

Horizontal translation in the $+x$ direction.

Step-by-step explanation:

A function of the form $f(x)$ experiments an horizontal translation when the following substitution is applied:

$x \to x + a$ , where $a \in \mathbb{R}$

If $a > 0$ , the function is translated in the $-x$ direction, whereas $a < 0$ is the case for the function being translated in the $+x$ direction.

The effect on the graph can be defined by a composition between two function:

$f(x) = x^{2}$ , $g (x) = x-6$

$f\,\circ\,g\,(x) = (x-6)^{2}$

The resulting expression represents a horizontal translation in the $+x$ direction.

Finally, we plot $f(x)$ (red) and $f\,\circ g\,(x)$ (blue) by a graphing tool and proved the certainty of this theory.

5 0

3 years ago

27+9+3- what is the answer?

Anit [1.1K]

Answer is 39 explanation I’m smart

4 0

2 years ago

Makovka662 [10]

Answer:

D is the answer

Step-by-step explanation:

this is the average growth of a plant

8 0

2 years ago

I need 3 values that would make the inequality true

Kitty [74]

15,16,17 this could be it

3 0

4 years ago