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omeli [17]
3 years ago
15

Write the ratio as a fraction in the lowest terms 17 minutes to 3 hours

Mathematics
1 answer:
Kryger [21]3 years ago
8 0
We know that there are 60 minutes in an hour, so to get the ratio to equal terms, we could multiply 60 by 3 to find the number of minutes in 3 hours, which is 90. Now the ratio is 17 minutes to 90 minutes. I'm pretty sure this is the lowest terms, but if they want you to convert it to seconds or something, you would multiply 17 by 60 for the first number and 90 by 60 for the second number. Hope this helps!
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Find the number to add to x^2-18x
pentagon [3]

Answer:

A. add 81; (x-9)^2

Step-by-step explanation:

The perfect square formula

(a-b)^2=a^2-2ab+b^2

Rewrite expression x^2-18x as follows:

x^2-2\cdot 9\cdot x

So, to form a perfect square, +9^2 is missed.

When we add 9^2=81, we will get

x^2-2\cdot 9\cdot x+9^2=(x-9)^2

4 0
3 years ago
Roberto purchased airline tickets for his family of 4. The tickets cost $1,250.The airline also charged a luggage fee,bringing t
goblinko [34]

Find the difference:

1400 - 1250 = 150

Divide the difference by the starting value:

150 / 1250 = 0.12

Multiply by 100:

0.12 x 100 = 12% increase.

3 0
3 years ago
Read 2 more answers
John wants to make a 100 ml of 6% alcohol solution mixing a quantity of a 3% alcohol solution with an 8% alcohol solution. What
mart [117]

Answer:

-50 ml of 3% alcohol solution and 150 ml of 8% alcohol solution

Step-by-step explanation:

For us to solve this type of mixture problem, we must represent the problem in equations. This will be possible by interpreting the question.

Let the original volume of the first alcohol solution be represented with x.

The quantity of the first alcohol solution needed for the mixture is 3% of x

                   ⇒ \frac{3}{100} * x

                       = 0.03x

Let the original volume of the second alcohol solution be represented with y.

The quantity of the second alcohol solution needed for the mixture is 5% of y

                   ⇒ \frac{5}{100} * y

                       = 0.05y

The final mixture of alcohol solution is 6% of 100 ml

                 ⇒ \frac{6}{100} * 100 ml

                       = 6 ml

Sum of values of two alcohol solutions = Value of the final mixture

                     0.03x + 0.05y = 6 ml               ..........(1)

Sum of original quantity of each alcohol solution = Original volume of the of mixture

                     x + y = 100 ml                          ..........(2)      

For easy interpretation, I will be setting up a table to capture all information given in the question.

Component                       Unit Value      Quantity(ml)       Value

3% of Alcohol solution        0.03                 x                     0.03x

8% of Alcohol solution        0.08                 y                     0.08y

Mixture of 100ml of 6%        0.06               100                       6    

                                                                x + y = 100       0.03x + 0.08y =6

Looking at the equations we derived, we have two unknowns in two equations which is a simultaneous equation.

                                0.03x + 0.05y = 6 ml               ..........(1)

                                x + y = 100 ml                           ..........(2)    

Using substitution method to solve the simultaneous equation.

Making x the subject of formula from equation (2), we have,

                                x  = 100 - y                                 ..........(3)

Substituting  x  = 100 - y from equation (3) into equation (1)

                               0.03(100 - y) + 0.05y = 6  

                               3 - 0.03y + 0.05y = 6  

Rearranging the equation,            

                               0.05y - 0.03y = 6 - 3

                               0.02y = 3

                               y = \frac{3}{0.02}

                               y = 150 ml

Substituting y = 150 ml into equation (3) to get x

                              x  = 100 - 150 ml

                              x = - 50 ml

The quantity of the first alcohol solution needed for the mixture for 3% is - 50 ml

The quantity of the second alcohol solution needed for the mixture for 5% is 150 ml

This solution means 50 ml of the first alcohol solution must be removed from the mixture with 150 ml of the second alcohol solution to get a final mixture of 100 ml of 6% alcohol solution.

3 0
2 years ago
Y + 1/2 = 7/10 solve for y
ahrayia [7]
It would be 2/10 or 1/5 simplified
7 0
3 years ago
Read 2 more answers
Julia wants to find out which color fabric will heat up the fastest when put under a direct light.
Tanya [424]

Answer:

No, she has more than one independent variable.

Step-by-step explanation:

8 0
3 years ago
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