Answer:
( -
/2 , -1/2)
Step-by-step explanation:
-210 degrees in standard position corresponds to an angle in the 3rd quadrant 30 degrees below the negative x-axis
The hypotenuse of the triangle here is 1, and we want the coordinates.
_______________________(0,0)
|(x = -root(3)/2)
|
| (y = -1/2)
Answer:
3hours and 15 mins
Step-by-step explanation:
210 divied by 3=70
70=per hour
4 hours=280
70 divied by 2= 35
.5=35
280+35=315
315 miles in 4.5 hours
Answer:
The answer to your question is: width = 3 meters
Step-by-step explanation:
Data
Perimeter = 16 meters
The room is 2 meters longer than its width, then length = width + 2
Perimeter = 2 length + 2 width
16 = 2(width + 2) + 2 width
16 = 2 width + 4 + 2 width
16 = 4 width +4
16 - 4 = 4 width
12 = 4 width
12/4 = width
3 = width
length = 3 + 2 = 5 meters
Answer:
x = 53
Step-by-step explanation:
22 - 3 ( x - 70 ) = x + 20 Multiply out
22 - 3x + 210 = x + 20
22 + 210 - 3x = x + 20
232 - 3x = x + 20
232 - 3x + 3x = x + 3x + 20
232 = 4x + 20
232 - 20 = 4x + 20 - 20
212 = 4x
212/4 = 4x/4
212/4 = x
x = 53
Answer:
a. 16π cm²
b. 24π cm²
c. 33 1/3π cm²
d. 64π-128 cm²
e. 144π-288 cm²
Step-by-step explanation:
To find area of shaded region, find area of whole circle then divide the area where you're left with the area of the shaded region. For the problems with the triangles you find the area of the triangle then subtract that from a fourth of the area of the circle.
Area of a circle = πr²
a.
r=8cm
Area of circle=64π cm²
Shaded region=16π cm²
b.
r=12cm
Area of circle=144π cm²
Shaded region=24π cm²
c.
r=10cm
Area of circle=100π cm²
Shaded region=33 1/3π cm²
d.
r=16cm
Area of circle=256π cm²
Area of triangle=128 cm²
Shaded region=64π-128 cm²
e.
r=24
Area of circle=576π cm²
Area of triangle=288 cm²
Shaded region=144π-288 cm²
