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3 years ago

If you invest x dollars at 3% intrest compounded annually ,then the amount A (x) of the investment after one year is A(x)=1.03x.

1 answer:

5 0

The "compound amount" formula is A = P(1+r)^t.

Here, the Amount A(x) is (x)(1+0.03)^1= 1.03x.

Please be clearer about what you are asking here. I assume you just wanted to be told that you are right.

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Jocelyn sells necklaces for $8 each. It costs her $20 for

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We see that the slope intercept is y = 8x - 20. So if we substitute x with 2, because x represents the amount of necklaces sold and we are analyzing her net profit after selling 2 necklaces, that gives us y = 8(2) - 20. Which simplifies to y = -4. So by the time Jocelyn sells 2 necklaces, her net profit will be at -4.

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3 years ago

Sandwich sales for one week are $1,275.00 and 300 sandwiches are sold. How much did each sandwich sell for assuming each sold fo

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Answer:

$4.25

Step-by-step explanation:

1275/300=425

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3 years ago

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Answer:

Step-by-step explanation:

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3 years ago

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Identify the quadrilateral that has four congruent angles that has two pairs of parallel sides

Anna11 [10]

Answer:

Rhombus

Step-by-step explanation:

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2 years ago

Jessica has a four-sided die, a six-sided die, and a 12-sided die. She rolls the three dice once. Let Z be the number of fours s

yawa3891 [41]

Answer:

The value of E [Z] is 0.50.

Step-by-step explanation:

The expected value is computed using the formula:

$E(X)=\sum x\cdot P(X= x)$

Denote the three dices as follows:

X₁ = a four-sided die

X₂ = a six-sided die

X₃ = a 12-sided die

Define the indicator variables as follows:

$I_{1}=\left \{ {{1;\ X_{1}=4} \atop {0;\ X_{1}\neq 4}} \right. \\\\I_{2}=\left \{ {{1;\ X_{2}=4} \atop {0;\ X_{2}\neq 4}} \right. \\\\I_{3}=\left \{ {{1;\ X_{3}=4} \atop {0;\ X_{3}\neq 4}} \right.$

The probability of rolling a 4 in the three dices are as follows:

$P(X_{1}=4)=\frac{1}{4}\\\\P(X_{2}=4)=\frac{1}{6}\\\\P(X_{3}=4)=\frac{1}{12}$

Compute the value of E [Z] as follows:

$E(Z)=E(I_{1})+E(I_{2})+E(I_{3})$

$=(1\times\frac{1}{4})+(1\times\frac{1}{6})+(1\times\frac{1}{12})\\\\=\frac{3+2+1}{12}\\\\=\frac{6}{12}\\\\=\frac{1}{2}\\\\=0.50$

Thus, the value of E [Z] is 0.50.

8 0

2 years ago