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4 years ago

You answer should say: Car _ by __ km/hr (Use care in answering!)

Mathematics

1 answer:

Lina20 [59]4 years ago

8 0

Answer:

Car B by 20km/hr

Step-by-step explanation:

well, we first calculate the speeds of both cars. there is an allocated dot along the 6 hour mark for the line graph of both cars. hence, using a time of 6 hours, we use their respective distances to produce an answer. car a has travelled 360 km while car v has travelled 480 km.

hence:

speed of car b = 480/6 = 80

speed of car a = 360/6 = 60

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Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given question. Listed below

mafiozo [28]

Answer:

a) $\bar X = 369.62$

b) $Median=175$

c) $Mode =450$

With a frequency of 4

d) $MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

<u>e)</u> $s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

Step-by-step explanation:

We have the following data set given:

49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000

Part a

The mean can be calculated with this formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

Replacing we got:

$\bar X = 369.62$

Part b

Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:

$Median=175$

Part c

The mode is the most repeated value in the sample and for this case is:

$Mode =450$

With a frequency of 4

Part d

The midrange for this case is defined as:

$MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

Part e

For this case we can calculate the deviation given by:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And replacing we got:

$s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

5 0

3 years ago

What is the slope of the line that passes through the points (-10, -8)(−10,−8) and (-8, -16) ?(−8,−16)? Write your answer in sim

photoshop1234 [79]

The slope of the line that passes through points ( -10, -8 ) and ( -8, -16 ) is -4.

<u>Explanation:</u>

Points given = ( -10, -8) and ( -8, -16)

Slope = ?

( -10, -8 ) : x1 = -10 and y1 = -8

( -8, -16 ) : x2 = -8 and y2 = -16

We know,

slope = y2 - y1 / x2 - x1

Slope = -16 - ( -8) / -8 - (-10)

slope = -16 + 8 / -8 + 10

slope = -8 / 2

slope = -4

Therefore, slope of the line that passes through points ( -10, -8 ) and ( -8, -16 ) is -4.

3 0

3 years ago

In the figure at the right DC = 20 cm and AB =36 cm . what is FE? a.16cm b.56cm c.28cm d.46cm

puteri [66]

Answer:

however dc =20 cm is

Step-by-step explanation:

so this isnt contrary to 50

6 0

2 years ago

Read 2 more answers

What is 15/8 equal to?

yKpoI14uk [10]

Answer:

1.875

Step-by-step explanation:

i hope this helps, have a good day!

6 0

3 years ago

Read 2 more answers

Please help me and explain it please questions 28

klasskru [66]

Answer:

$1.35

Step-by-step explanation:

x: quarter=$0.25

y: dime=$0.10

z: nickel=$0.05

so total amount of changes

= (0.25*x)+(0.10*y)+(0.05*z)

x=3, y=5, z=2

substituting into the eqn

total = (0.25*3)+(0.10*5)+(0.05*2)

= 0.75 + 0.5 + 0.1

= $1.35

5 0

3 years ago

Read 2 more answers