A parabolic function's key characteristic is either having 2 x-intercepts or 2 y-intercepts. That is the reason why the standard form of parabolic functions are:
(x-h)^2 = +/- 4a(y-k) or (y-k)^2 = +/- 4a(x-h), where
(h,k) is the coordinates of the vertex
4a is the lactus rectum
a is the distance from the focus to the vertex
This is also called vertex form because the vertex (h,k) is grouped according to their variable.
Since we don't know any of those parameters, we'll just have to graph the data points given as shown in the picture. From this data alone, we can see that the parabola has two x-intercepts, x=-4 and x=-2. Since it has 2 roots, the parabola is a quadratic equation. Its equation should be
y = (x+4)(x+2)
Expanding the right side
y = x²+4x+2x+8
y = x²+6x+8
Rearrange the equation such that all x terms are on one side of the equation
x²+6x+___=y-8+___
The blank is designated for the missing terms to complete the square. Through completing the squares method, you can express the left side of the equation into (x-h)² form. This is done by taking the middle term, dividing it by two, and squaring it. So, (6/2)²=9. Therefore, you put 9 to the 2 blanks. The equation is unchanged because you add 9 to both sides of the equation.
The final equation is
x²+6x+9=y-8+9
(x+3)²=y+1
6. 5 shirts 20 minutes Multiply both by 3 to get to 60 minutes
15 shirts 60 minutes
15 shirts per hour
7. 250 miles + 50 miles = 300 miles
300 miles / 5 hours = 60 miles per hour
8. 360 pages / 12 hours = 30 pages per hour400 pages / 30 pages per hour = 13 1/3 hours
= 13 hours and 20 minutes
ACB + BAC =90
ACB + 37 = 90
ACB = 53
Tan (53) = 10/x
X= 7.536
(Hope this helped have a great day)
15-27b+11=-244
26-27b=-244
-27b=-270
b=10
Answer:
Step-by-step explanation:
S A S congruence rule: Two triangles are congruent if two sides and the included angle of one triangle are equal to the two sides and the included angle of other triangle.
If two triangles are congruent by SAS, and the angle is 90, then by CPCT{corresponding part of congruent triangle) the hypotenuse of the two triangles will be congruent.
Now, as hypotenuse and one leg are congruent in both triangles, we can apply RHS congruent