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aivan3 [116]
3 years ago
13

Peter participated in a 5 k race and finished the race in 17 min. A 5 k race is 5,000 m long. How would you calculate peters ave

rage speed in m/min?
Mathematics
2 answers:
svetoff [14.1K]3 years ago
5 0

Answer: Peters average speed in m/min is 294.1176 m/min


Step-by-step explanation:


Peter participated in a 5000m race and finished the race in 17 min.


Speed is calculated as Distance/Time


Peters average speed in m/min = Distance covered in m / Time taken in minutes

= 5000/17

= 294.1176 m/min


Therefore, Peters average speed in m/min = 294.1176 m/min


Hope it helps.


Thank you :)




neonofarm [45]3 years ago
4 0

Answer:

294.12 m/min

Step-by-step explanation:

We are given that Peter participated in a 5k race.

Time =17 min.

5 k race represent length=5000 m

We  have to find the peters average speed in m/min.

We know that

Average speed=\frac{Distance}{time}

Using the formula

Average speed of Peter=\frac{5000}{17}=294.12 m/min

Hence, the average speed of Peter=294.12 m/min

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12 is what percent of 96
DaniilM [7]
12 * 100 = 1200/96 = 12.5 
Answer = 12.5%
You mulitply 12 by a hunndred, since a percent means "out of a hundred." Then, you divide that, by 96, since, you want to find the percent out of 96.

8 0
2 years ago
Suppose that the functions s and t are defined for all real numbers x as follows.
jeka94

Answer:

(s.t)(x) = 4x^2+24x^2\\(s-t)(x) = x+6-4x^2\\(s+t)(-3) = 39

Step-by-step explanation:

Given functions are:

s(x)= x+6\\t(x)= 4x^2

We have to find:

(s.t)(x) => this means we have to multiply the two functions to get the result.

So,

(s.t)(x) = s(x)*t(x)\\= (x+6)(4x^2)\\=4x^2.x+4x^2.6\\=4x^3+24x^2

Also we have to find

(s-t)(x) => we have to subtract function t from function s

(s-t)(x) = s(x) - t(x)\\= (x+6) - (4x^2)\\=x+6-4x^2

Also we have to find,

(s+t)(-3) => first we have to find sum of both functions and then put -3 in place of x

(s+t)(x) = s(x)+t(x)\\= x+6+4x^2

Putting x = -3

= -3+6+4(-3)^2\\=-3+6+4(9)\\=3+36\\=39

Hence,

(s.t)(x) = 4x^2+24x^2\\(s-t)(x) = x+6-4x^2\\(s+t)(-3) = 39

8 0
2 years ago
Calculate the length of ac
svlad2 [7]

Answer:

  12.1 cm

Step-by-step explanation:

Using the law of sines, we can find angle C. Then from the sum of angles, we can find angle B. The law of sines again will tell us the length AC.

  sin(C)/c = sin(A)/a

  C = arcsin((c/a)sin(A)) = arcsin(8.2/13.5·sin(81°)) ≈ 36.86°

Then angle B is ...

  B = 180° -A -C = 180° -81° -36.86° = 62.14°

and side b is ...

  b/sin(B) = a/sin(A)

  b = a·sin(B)/sin(A) = 13.5·sin(62.14°)/sin(81°) ≈ 12.0835

The length of AC is about 12.1 cm.

_____

<em>Comment on the solution</em>

The problem can also be solved using the law of cosines. The equation is ...

  13.5² = 8.2² +b² -2·8.2·b·cos(81°)

This is a quadratic in b. Its solution can be found using the quadratic formula or by completing the square.

  b = 8.2·cos(81°) +√(13.5² -8.2² +(8.2·cos(81°))²)

  b = 8.2·cos(81°) +√(13.5² -(8.2·sin(81°))²) . . . . . simplified a bit

3 0
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What value of k will result in the quadratic having one rational solution if 4x2+kx+4=0?
PtichkaEL [24]

The value of 'k' in the quadratic Equation    4x^{2}+kx+4=0 having one rational solution is k is 8.

<h3>What is a Quadratic Equation?</h3>
  • Quadratic equations are the polynomial equations of degree 2 in one variable of the type f(x) = ax^{2} + bx + c = 0 where a, b, c, ∈ R and a ≠ 0.
  • The standard form of a quadratic equation is ax^{2} + bx + c = 0 .

Here, the given equation is  4x^{2}+kx+4=0

By comparing the given equation with the standard form of the quadratic equation we get,

a = 4

b = k

c = 4

The given quadratic is having one rational solution, which means b^{2} -4ac=0

Therefore,

k^{2} -4 \times 4\times4=0\\k^{2} -64=0\\k^{2} =64\\k=\sqrt{64} \\k=8

Therefore, the value of k is 8.

Learn more about the quadratic equation is brainly.com/question/8649555

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