All categories

3 years ago

Find the distance between M (-1,-1 ) and H (1,-2)

Mathematics

1 answer:

dolphi86 [110]3 years ago

4 0

Answer:

sqrt(5)

Step-by-step explanation:

I hope this helps

You might be interested in

Find the exact value of tan 15 degrees

pentagon [3]

<span>tan(15) =
sin(15) / cos(15) =
sin(45 - 30) / cos(45 - 30) =
[ sin(45)cos(30) - sin(30)cos(45) ] / [ cos(45)cos(30) + sin(45)sin(30)]

Since sin(45) = cos(45) = √2/2, you can just factor that out from the top and bottom
[ cos(30) - sin(30) ] / [ cos(30) + sin(30)]
[ √3/2 - 1/2 ] / [ √3/2 + 1/2]
(√3 - 1) / (√3 + 1)
(√3 - 1)^2 / (√3+1)(√3 - 1)
(√3 - 1)^2 / (3 - 1)
(3 - 2√3 +1) / 2
2 - √3

There's also a formula for tan(a-b), but I couldn't remember it off hand.</span>

4 0

3 years ago

A restaurant plans to a buy a total of 3,006

kotegsom [21]

Answer: The question isn't finished.

Step-by-step explanation:

7 0

3 years ago

-x+3=-3d-3r, for x .

OLga [1]

Answer:

x=3d+3r+3

Step-by-step

5 0

3 years ago

What number is it that, when multiplied by 18,27,36,45,54,63,72,81, or 99, gives a product in which the first and last figures a

allsm [11]

The given multipliers are factors of 9, the possible number will have 1 as first and last digit which gives the number as 101

<h3>How can the correct number be found?</h3>

The given numbers are;

18, 27, 36, 45, 54, 63, 72, 81, 99

Given that the first and the last figures are those of the multipliers, we have;

The first and last and last digit of the number can be 1, which gives;

Possible numbers includes; 11 and 101

By trying the possible numbers, the difference found is presented as follows;

99 × 11 = 1089 (The first and the last digit are not the same as the multiplier)

99 × 101 = 9999 (First and last digit are not the same as the multiplier)

90 × 11 = 990

90 × 101 = 9090

The correct option is therefore 101

The number is 101

Learn more about multiplication of numbers here:

brainly.com/question/83239

#SPJ1

6 0

2 years ago

Question 1: Describe in words the region of double-struck R3 represented by the equation: x2 + z2 ≤ 36.

Ganezh [65]

Step-by-step explanation:

1) i will asume x2 and z2 are squares here.

ok, here we only have restrictions to x and z, so y can take all the values in R.

$x^{2} + z^{2} \leq 36$ is a circle of radius 6, you can see this if for example we set z = 0, then x goes from -6 to 6, the same if we set x = 0 then z goes from -6 to 6.

and the equation $x^{2} + z^{2} \\$ describes a circle.

So here, the region is the solid cylinder of radius 6, where the Y axis is also the axis of the cylinder.

2) you tipped the same inequality but different numbers in the right side, here i think you are saying that the inequalities describes the set of all points whose distance from the y-axis is equal or less tan 6.

7 0

3 years ago