Answer:
b
Step-by-step explanation:
Given
x³ + 5x² - 9x - 45 ( factor the first/second and third/fourth terms )
= x²(x + 5) - 9(x + 5) ← factor out (x + 5) from each term
= (x + 5)(x² - 9) ← factor as a difference of squares
= (x + 5)(x - 3)(x + 3)
Answer:
Decimal
Step-by-step explanation:
The 37 and the 2 is separated by that little dot called a decimal.
Given plane Π : f(x,y,z) = 4x+3y-z = -1
Need to find point P on Π that is closest to the origin O=(0,0,0).
Solution:
First step: check if O is on the plane Π : f(0,0,0)=0 ≠ -1 => O is not on Π
Next:
We know that the required point must lie on the normal vector <4,3,-1> passing through the origin, i.e.
P=(0,0,0)+k<4,3,-1> = (4k,3k,-k)
For P to lie on plane Π , it must satisfy
4(4k)+3(3k)-(-k)=-1
Solving for k
k=-1/26
=>
Point P is (4k,3k,-k) = (-4/26, -3/26, 1/26) = (-2/13, -3/26, 1/26)
because P is on the normal vector originating from the origin, and it satisfies the equation of plane Π
Answer: P(-2/13, -3/26, 1/26) is the point on Π closest to the origin.
Answer:
B
Step-by-step explanation:
To go from 6 to 9 you'd first have to divide 6 by 2 and the multiply by 3,
so 
x 3 = 
Answer:
1.7689 (rounded to 4 decimal places)
Step-by-step explanation:
Let the number we are seeking be "x", thus we can write the equation as:
Since we have raised "x" to the "10th power", to get "x" back again, we need to take 10th root. Same goes for right side, we take 10th root of 300. We will get our answer. The process shown below:
![x^{10}=300\\\sqrt[10]{x^{10}} =\sqrt[10]{300} \\x=\sqrt[10]{300} \\x=1.7689](https://tex.z-dn.net/?f=x%5E%7B10%7D%3D300%5C%5C%5Csqrt%5B10%5D%7Bx%5E%7B10%7D%7D%20%3D%5Csqrt%5B10%5D%7B300%7D%20%5C%5Cx%3D%5Csqrt%5B10%5D%7B300%7D%20%5C%5Cx%3D1.7689)
hence, 1.7689 raised to 10th power will give us 300
