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Savatey [412]
2 years ago
12

Paul rents a car for $30 a day. Write an expression to show the relationship between the number of days Paul rents the car and t

he total dollars (t) he spends?​
Mathematics
1 answer:
rosijanka [135]2 years ago
3 0

The expression that can be used to show the relationship between the number of days and the total dollars (t) he spends is t = 30d

<h3>How to write expressions</h3>

  • Cost of renting a car per day = $30
  • Number of days Paul rents the car = d
  • Total amount John spends = $t

The equation:

Total = cost per day × number of days

t = 30 × d

t = 30d

Learn more about equation:

brainly.com/question/13763238

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Log(x-2)+log2=2logy<br>log(x-3y+3)=0​
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Answer:

<h2>x = 4 and y = 2 or x = 10 and y = 4</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}\log(x-2)+\log2=2\log y&(1)\\\log(x-3y+3)=0&(2)\end{array}\right

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\log(3y-2-2)+\log2=2\log(y)\qquad\text{use}\ \log_ab^n=n\log_ab\\\\\log(3y-4)+\log2=\log(y^2)\qquad\text{subtract}\ \log(y^2)\ \text{from both sides}\\\\\log(3y-4)+\log2-\log(y^2)=0\\\\\text{Use}\ \log_ab+\log_ac=\log_a(bc)\ \text{and}\ \log_ab-\log_ac=\log_a\dfrac{b}{c}\\\\\log\dfrac{(3y-4)(2)}{y^2}=0\qquad\text{use}\ \log_ab=0\Rightarrow b=1\\\\\dfrac{(3y-4)(2)}{y^2}=1\iff y^2=(3y-4)(2)\\\\\text{Use the distributive property}\ a(b+c)=ab+ac

y^2=(3y)(2)+(-4)(2)\\\\y^2=6y-8\qquad\text{subtract}\ 6y\ \text{from both sides}\\\\y^2-6y=-8\qquad\text{add 8 to both sides}\\\\y^2-6y+8=0\\\\y^2-2y-4y+8=0\\\\y(y-2)-4(y-2)=0\\\\(y-2)(y-4)=0\iff y-2=0\ \vee\ y-4=0\\\\\boxed{y=2\ \vee\ y=4}\in D

\text{Put the values of}\ y\ \text{to }\ (*):\\\\\text{for}\ y=2:\\\\x=3(2)-2\\\\x=6-2\\\\\boxed{x=4}\in D\\\\\text{for}\ y=4:\\\\x=3(4)-2\\\\x=12-2\\\\\boxed{x=10}\in D

4 0
3 years ago
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skad [1K]

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a.

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Step-by-step explanation:

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Answer:

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4 0
4 years ago
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Answer: -136

Step-by-step explanation:

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*edited* I believe this is correct

8 0
3 years ago
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