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dem82 [27]
3 years ago
11

How is communication different from data transfer?

Computers and Technology
1 answer:
omeli [17]3 years ago
6 0
Communication is like a debate data is facts that’s been studied
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A Color class has three public, integer-returning accessor methods: getRed, getGreen, and getBlue, and three protected, void-ret
jek_recluse [69]

Answer:

The following code are:

public void dissolve() {

setRed(getRed()+1);

setGreen(getGreen()+1);

setBlue(getBlue()+1);

alpha+=1;

}

Explanation:

Here, we define the void type function "dissolve()" inside it, we set three function i.e, "setRed()", "setGreen()", "setBlue()" and then we increment the variable "alpha" by 1.

Inside those three mutators method we set three accessor methods i.e, "getRed()", "getGreen()" , "getBlue()" and increment these accessor by 1.

The values will not be returned by the mutator functions, the accessor will be returned the values.

6 0
3 years ago
Write c++ code that prints: usernum ... 2 1 blastoff! your code should contain a for loop. print a newline after each number and
nata0808 [166]
#include <iostream>
int main() { int usernum = 3;
for(int i = usernum; i >= 1; i--) { std::cout << i << "\n"; } std::cout << "blastoff!\n";
return 0;}
Works fine my dude:
./randombrainly 321blastoff!
3 0
4 years ago
When a policy setting in Computer Configuration and User Configuration in the same GPO conflict, the Computer Configuration poli
Maru [420]

Answer:

True

Explanation:

Computer Configuration policy applied first. This happens when the Computer system boots up. Then the user policy is applied when the user logs on. This takes place when the user object is in the same organizational unit.

So Computer Config policy setting takes precedence. User configurations is applied to local users only while computer configuration is applied to the machine itself. First the Computer GPO is applied and then the User GPO.  Loopback processing in replace mode enforces the Computer GPO over the user GPO.

8 0
4 years ago
A _____ is a collection of binary digits, including message data and control characters for formatting and transmitting, sent fr
Keith_Richards [23]

Answer:

Packet

Explanation:

8 0
3 years ago
Write a program that could find whether the number entered through keyboard is odd or even the program should keep on taking the
natulia [17]

Answer:

using namespace std;

int main() {

int number;

while (1) {

 cout << "Enter a number: ";

 cin >> number;

 cout << number << " is " << ((number % 2) ? "odd" : "even") << endl;

};

return 0;

}

Explanation:

This is a c++ version. Let me know if you need other languages.

The (number % 2) is the essence of the program. It returns 0 for even numbers, and 1 for odd numbers (the remainder after division by 2).

7 0
4 years ago
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