The correct answer is b. Release of short-chain fatty acids.
The intestinal microflora is complex ecosystem which contains over 400 bacterial species.That microflora is capable of fermenting indigestible carbohydrates (dietary fiber) to short-chain fatty acids such as acetate, propionate, and butyrate.
The correct answer is: the " phospholipid bilayer " .
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→ { which is hydrophobic (water-repellent) due to its waxy-like composition of many lipids.}.
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Hope this helps you!
Best wishes!
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The likelihood that the first two offspring of the cross will have congenital analgesia would be 1/16
<h2>Autosomal Recessive Traits</h2>
For autosomal recessive traits, two recessive alleles are needed for the trait to manifest while one recessive allele means heterozygosity.
In this case, let us assume that congenital analgesia is represented by the allele b; heterozygous individuals will, thus, be Bb.
Bb x Bb
BB Bb Bb bb
Probability of producing unaffected offspring = 3/4
Probability of producing affected offspring = 1/4
Likelihood of the first two offspring having congenital analgesia = probability of first having congenital analgesia and the second having congenital analgesia
= 1/4 x 1/4
= 1/16
More on genetical probabilities can be found here: brainly.com/question/851793?referrer=searchResults
Answer:
A. carbon dioxide molecules C. glucose molecules
Explanation:
Suppose you have an EMP. You install the EMP to a temporary data distiller. The data you get back reads simply static.
