The minimum value for 2x is 0
<span>the maximum value is achieved when A, D and C are collinear and the quadrilateral ABCD becomes an isosceles triangle ABC </span>
<span>base AB = 52 and vertical angle 2x + 34° </span>
<span>For the sine law </span>
<span>(sin 2x)/22 = (sin ADB)/AB </span>
<span>(sin 34°)/30 = (sin BDC)/BC </span>
<span>is given that AB = BC, and sin ADC = sin BDC because they are supplementary, so from </span>
<span>(sin ADC)/AB = (sin BDC)/BC </span>
<span>it follows </span>
<span>(sin 2x)/22 = (sin 34°)/30 </span>
<span>sin 2x = 22 (sin 34°)/30 </span>
<span>2x = asin(22 (sin 34°)/30) ≈ 24.2° </span>
<span>x = 0.5 asin(22 (sin 34°)/30) ≈ 12.1° </span>
<span>0 < x < 12.1°</span>
Answer:
m∠x ≈ 32°
Step-by-step explanation:
We can see that we have to use tan∅ to solve this (opposite over adjacent)
tan(x) = 7/11
x = tan^-1 (7/11)
x = 32.4712
