I’m guessing that this is for systems of equations?
n - nickels
d - dimes
These are the equations you start off with.
n = 5d-2
0.95 = 0.10d+0.05n
Substitute the top equation for n into the variable n in the bottom equation.
0.95 = 0.10d+0.05(5d-2)
Solve for d.
0.95 = 0.10d+0.25d-0.10
1.05 = 0.35d
3 = d
Substitute d into the top equation and solve for n.
n = 5(3)-2
n = 15-3
n = 12
There are 3 dimes and 12 nickels in the coin purse! Hope this helped <3
Answer:
![4\sqrt[3]{7x}](https://tex.z-dn.net/?f=4%5Csqrt%5B3%5D%7B7x%7D)
Step-by-step explanation:
Look for the same stuff under the radical symbol. Here, that "stuff" is "7x". Only one answer choice has 7x under the radical.
_____
Here, there are no cubic factors under the radical that can be factored out—either in the problem expression or in the answer choices. If there were cubic factors, you'd want to remove them before making the comparison.
For example, ∛(56x) would be a like radical to ∛(7x) because a cubic factor of 2^3 = 8 can be removed to make it be 2∛(7x).
Answer:
Step-by-step explanation:
I could help you in chat if you text me
<h3>Answer:</h3>
y = -3(x -2)² -5
<h3>Explanation:</h3>
The equation of a parabola with vertex (h, k) is given by ...
... y = a(x -h)² +k . . . . . . . for some vertical scale factor "a".
We can find the value of "a" by substituting the coordinates of a point that is not the vertex. Here, that point is the y-intercept: (0, -17).
... y = a(x -2)² -5 . . . . . initial form of the equation for the parabola
... -17 = a(-2)² -5 . . . . . substitute y-intercept values
... -12 = 4a . . . . . . . . . . add 5, simplify
... -12/4 = a = -3
The desired equation is ... y = -3(x -2)² -5.