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olga_2 [115]
3 years ago
10

PLEASSSSSEEEEE HELP ME THIS IS DUE PRETTY SOON I REALLY NEED THE FULL EXPLANATION.

Mathematics
2 answers:
Anastaziya [24]3 years ago
4 0

Answer:

a. 14,4 miles per gallon

b. 15 miles per gallon

c. Mr. Walters' car

Step-by-step explanation:

a. Mrs. Walters drove 360 miles on 25 gallons, so she is drives 360 ÷ 25 = 14,4 miles per gallon

b. Mr. Walters drove 480 miles on 32 gallons, so he drives 480 ÷ 32 = 15 miles per gallon

c. 15 > 14.4 therefore, Mr. Walters' car is getting the better mileage per gallon

user100 [1]3 years ago
3 0

Answer:

a-14.4 MPG, B-15 MPG c Mr. Walters

Step-by-step explanation:

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What is The productöt 9 and 5/8 ?
Karolina [17]

Answer: 45/8 or 5 5/8

Step-by-step explanation:

9   5 = 45

1    8 = 8

45/8=5 and 5/8

8 0
2 years ago
Which number would divide the numerator and the denominator of the first fraction to yield the second fraction? 14 18 ÷ ? ? = 7
Paha777 [63]

Step-by-step explanation:

14÷2=7

18÷2=9

for the first equation

14/y=7

cross multiply will be

7y=14

divide both sides by the co efficient of y which is 7

y=14÷2

y=2

same step for the second equation

6 0
2 years ago
Can someone help me asap!!!
amm1812

Answer:

<em>Negative</em>

Step-by-step explanation:

5 0
2 years ago
Which shows 23/5 as a mixed number?
satela [25.4K]

Answer:4 3/5

Step-by-step explanation:

3 0
3 years ago
Sinx = 1/2, cosy = sqrt2/2, and angle x and angle y are both in the first quadrant.
Leviafan [203]

Answer:

Option D. 3.73​

Step-by-step explanation:

we know that

tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}

and

sin^{2}(\alpha)+cos^{2}(\alpha)=1

step 1

Find cos(X)

we have

sin(x)=\frac{1}{2}

we know that

sin^{2}(x)+cos^{2}(x)=1

substitute

(\frac{1}{2})^{2}+cos^{2}(x)=1

cos^{2}(x)=1-\frac{1}{4}

cos^{2}(x)=\frac{3}{4}

cos(x)=\frac{\sqrt{3}}{2}

step 2

Find tan(x)

tan(x)=sin(x)/cos(x)

substitute

tan(x)=1/\sqrt{3}

step 3

Find sin(y)

we have

cos(y)=\frac{\sqrt{2}}{2}

we know that

sin^{2}(y)+cos^{2}(y)=1

substitute

sin^{2}(y)+(\frac{\sqrt{2}}{2})^{2}=1

sin^{2}(y)=1-\frac{2}{4}

sin^{2}(y)=\frac{2}{4}

sin(y)=\frac{\sqrt{2}}{2}

step 4

Find tan(y)

tan(y)=sin(y)/cos(y)

substitute

tan(y)=1

step 5      

Find tan(x+y)

tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}

substitute

tan(x+y)=[1/\sqrt{3}+1}]/[{1-1/\sqrt{3}}]=3.73

7 0
3 years ago
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