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STatiana [176]
3 years ago
7

HELP! 30 pts! The circle below is centered at the point (-2, -3) and has a radius of length 3.

Mathematics
1 answer:
statuscvo [17]3 years ago
3 0

Answer:

(x + 2)^2 + (y + 3)^2 = 9

Step-by-step explanation:

Center = (-2, - 3) = (h, k)

Radius (r) = 3

Equation of circle in centre radius form is given as:

(x - h) ^2 + (y - k) ^2 = r^2 \\\therefore \{x - (-2)\}^2 + \{y - (-3)\}^2 = 3^2 \\ \purple {\boxed {\bold {\therefore(x + 2)^2 + (y + 3)^2 = 9}}}

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\large\begin{array}{l} \textsf{b) }\mathsf{(g\circ f)(-2)}\\\\ =\mathsf{g\big[f(-2)\big]}\\\\ =\mathsf{\sqrt{f(-2)}}\\\\ =\mathsf{\sqrt{(-2)^2-6\cdot (-2)+2}}\\\\ =\mathsf{\sqrt{4+12+2}}\\\\ =\mathsf{\sqrt{18}}\\\\ =\mathsf{\sqrt{3^2\cdot 2}}\\\\ =\mathsf{3\sqrt{2}}\\\\\\ \therefore~~\boxed{\begin{array}{c}\mathsf{(g\circ f)(-2)=3\sqrt{2}} \end{array}}\qquad\checkmark \end{array}

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If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2181559


\large\textsf{I hope this helps. :-)}


Tags: <em>composite function composition evaluate algebra</em>

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