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Semmy [17]
3 years ago
15

3sailboat to 6 fan boats

Mathematics
1 answer:
tia_tia [17]3 years ago
3 0
Answer:

1 sailboats : 2 fan boats

Explanation:

~ Simple ratio, we can just simplify 3:6.

~ We divide 3:6 by 3 which will give you 1:2.

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sattari [20]

the value of x is 36. is it right or wrong?

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4 years ago
You own a car wash with 3 of your friends you total profit in the first month was $438. in two months, each of you had made a pr
liubo4ka [24]
736 dollar

184 x 4 people= 736
5 0
3 years ago
Find the value of x.<br><br>• 5<br>• 20<br>• 40<br>• 45​
insens350 [35]

Answer:

3rd option: x= 40

Step-by-step explanation:

4x° +20°= 180° (adj. ∠s on a str. line)

<em>Bringing</em><em> </em><em>constants</em><em> </em><em>to</em><em> </em><em>1</em><em> </em><em>side</em><em>:</em>

4x°= 180° -20°

<em>Simplify</em><em>:</em>

4x°= 160°

<em>Divide</em><em> </em><em>by</em><em> </em><em>4</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>:</em>

x°= 40°

Thus, x=40.

7 0
4 years ago
. Given ????(5, −4) and T(−8,12):
damaskus [11]

Answer:

a)y=\dfrac{13x}{16}-\dfrac{129}{16}

b)y = \dfrac{13x}{16}+ \dfrac{37}{2}

Step-by-step explanation:

Given two points: S(5,-4) and T(-8,12)

Since in both questions,a and b, we're asked to find lines that are perpendicular to ST. So, we'll do that first!

Perpendicular to ST:

the equation of any line is given by: y = mx + c where, m is the slope(also known as gradient), and c is the y-intercept.

to find the perpendicular of ST <u>we first need to find the gradient of ST, using the gradient formula.</u>

m = \dfrac{y_2 - y_1}{x_2 - x_1}

the coordinates of S and T can be used here. (it doesn't matter if you choose them in any order: S can be either x_1 and y_1 or x_2 and y_2)

m = \dfrac{12 - (-4)}{(-8) - 5}

m = \dfrac{-16}{13}

to find the perpendicular of this gradient: we'll use:

m_1m_2=-1

both m_1and m_2 denote slopes that are perpendicular to each other. So if m_1 = \dfrac{12 - (-4)}{(-8) - 5}, then we can solve for m_2 for the slop of ther perpendicular!

\left(\dfrac{-16}{13}\right)m_2=-1

m_2=\dfrac{13}{16}:: this is the slope of the perpendicular

a) Line through S and Perpendicular to ST

to find any equation of the line all we need is the slope m and the points (x,y). And plug into the equation: (y - y_1) = m(x-x_1)

side note: you can also use the y = mx + c to find the equation of the line. both of these equations are the same. but I prefer (and also recommend) to use the former equation since the value of 'c' comes out on its own.

(y - y_1) = m(x-x_1)

we have the slope of the perpendicular to ST i.e m=\dfrac{13}{16}

and the line should pass throught S as well, i.e (5,-4). Plugging all these values in the equation we'll get.

(y - (-4)) = \dfrac{13}{16}(x-5)

y +4 = \dfrac{13x}{16}-\dfrac{65}{16}

y = \dfrac{13x}{16}-\dfrac{65}{16}-4

y=\dfrac{13x}{16}-\dfrac{129}{16}

this is the equation of the line that is perpendicular to ST and passes through S

a) Line through T and Perpendicular to ST

we'll do the same thing for T(-8,12)

(y - y_1) = m(x-x_1)

(y -12) = \dfrac{13}{16}(x+8)

y = \dfrac{13x}{16}+ \dfrac{104}{16}+12

y = \dfrac{13x}{16}+ \dfrac{37}{2}

this is the equation of the line that is perpendicular to ST and passes through T

7 0
3 years ago
What is the solution to the equation below?<br> log7+log(x-4)= 1
Mila [183]

Answer: x=38/7

Step-by-step explanation:

8 0
3 years ago
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