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Semmy [17]
3 years ago
15

3sailboat to 6 fan boats

Mathematics
1 answer:
tia_tia [17]3 years ago
3 0
Answer:

1 sailboats : 2 fan boats

Explanation:

~ Simple ratio, we can just simplify 3:6.

~ We divide 3:6 by 3 which will give you 1:2.

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Dok = (6, 12) (3,6)<br> The scale factor is<br> A. 1/2<br> B. 2<br> C. 4
Serga [27]

Answer:

A. 1/2

Step-by-step explanation:

For 6 to become 3 and 12 to become 6, the (6,12) is being multiplied by 1/2.

5 0
3 years ago
Read 2 more answers
What’s the answer???
Aleonysh [2.5K]

Answer:

the answer is a

you can subsitute or work backwards

6 0
4 years ago
Read 2 more answers
Now that you have x² - 8x 16 = 9 16, apply the square root property to the equation.
vitfil [10]

The square root property to the equation will be (x – 4)² = 25. And the solutions will be the negative 1 and 9.

<h3>What is a quadratic equation?</h3>

The quadratic equation is given as ax² + bx + c = 0. Then the degree of the equation will be 2. Then we have

The equation is given below.

x² – 8x + 16 = 9 + 16

Then the equation can be written as

(x – 4)² = 25

x – 4 = ±5

x = 4 ± 5

x = -1, 9

More about the quadratic equation link is given below.

brainly.com/question/2263981

#SPJ1

8 0
2 years ago
Suppose that two teams are playing a series of games, each of which is independently won by team A with probability p and by tea
Lady_Fox [76]

Answer:

4 games played = 1/56

5 games played = 5/56

6 games played = 15/56

7 games played = 35/56

Step-by-step explanation:

The probability of each time winning is 0.5

So there are a couple of ways the series could go.

  1. Team A could win all first 4 matches. We can depict this as A-A-A-A
  2. Team A could win 4, while having lost 1.  Lets depict this a A-B-A-A-A
  3. Team A could win 4, while having lost 2. A-B-B-A-A-A
  4. Team A could win 4, while having lost 3. A-B-B-B-A-A-A

These 4 possibilities could be repeated with B winning as well. It should be noted that these are the only ways for the series to end. We find the number of permutations of each possibility above to find their probability.

I advise you to study 'how to permute identical objects' for this.

These permutations are stated below:

1. 4!/4! = 1

2. \frac{5!}{4! * 1!} = 5

3 \frac{6!}{4! * 2!} = 15

4 \frac{7!}{4! * 3!} = 35

These are they ways A or B could win. The total is 1+5+15+35 = 56. The answer given thus reflects the possibilities.

4 0
4 years ago
If the solution to the equation is x = -2, find the value of a<br> 4x-2(x-a)= 14
tamaranim1 [39]


x=-2

4x-2(x-a)=14

4*(-2) -2(-2-a)=14

-8+4+2a=14

-4+2a=14

2a=18

<em><u /><u>a=9</u></em>

8 0
3 years ago
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