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kolbaska11 [484]
4 years ago
15

What is 1/3(3x-6)^3+4<13​

Mathematics
1 answer:
sesenic [268]4 years ago
5 0

Answer:

x

Step-by-step explanation:

\frac{1}{3}(3x-6)^3+4

Solving the inequality to have solutions for x

Subtracting 4 from both sides.

⇒ \frac{1}{3}(3x-6)^3+4-4

⇒ \frac{1}{3}(3x-6)^3

Multiplying 3 both sides to remove fraction.

⇒ 3\times \frac{1}{3}(3x-6)^3

⇒ (3x-6)^3

Taking cube root both sides to remove the cube.

⇒ \sqrt[3]{(3x-6)^3}

⇒ (3x-6)                [ ∵ \sqrt[3]{27} =3 ]

Adding 6 to both sides.

⇒ 3x-6+6

⇒ 3x

Dividing both sides by 3

⇒ \frac{3x}{3}

∴ x

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Answer:

joint variation means L (safe load) is directly proportional to both w and d2

inverse proportionality means L = k/l

So the equation is:

L = k(wd2/l)

You are given:

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d = 5 in

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L = 7666 lbs

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Solve for the constant, k.

7666 = k (6*25/12)

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7666 = k (12.5)

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Use this k-value to solve for L in the last part of the question.

What safe load, L would a beam 3 in. wide, 7 in. deep and 15 ft long of the same material support? (Round off your answer to the nearest pound.)

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d =7 in

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Final Safe load = 6010.144 lbs *** Edited for clarity and to fix a multiplication erro

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Find the area of the lateral faces of the right triangular prism with altitude of 5 cm and base edges of length 3 cm, 4 cm, and
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We know that
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the answer is
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