Question

The lengths of the two sides of a triangle (not necessarily a right triangle) are 1.00 meters and 3.54 meters. The sine of the angle opposite the side of length 1.00 meters is 0.0272. What is the sine of the angle opposite the side of length 3.54 meters?

Answer 1

Answer:

sin B= 0.096288

B = 5.525°

Step-by-step explanation:

Consider ΔABC as shown in figure attached

From figure:

a = 1 m

b = 3.54 m

sin A = 0.0272

sin B = ?

Using the sine rule for non-right-angle triangle

$\\\frac{a}{sin\, A}=\frac{b}{sin\,B}\\\\sin\,B=\frac{b(sin\,A)}{a}\\\\sin\,B=\frac{(3.54)(0.0272)}{1}\\\\sin\,B=0.096288\\\\B= 5.525^o$