Question

The function y = h(x) is defined as follows: (picture of question shown)

Answer 1

Answer:

$h(1)=1$ and $h(4)=5$

Step-by-step explanation:

We are given the function,

$h(x)=\left\{\begin{matrix}x^2,&x$

Since, when x= 1, the function is $h(x)=x^2$

Then, $h(1)=(1)^2= 1$

Also, when x= 4, the function is $h(x)=5$

That is, $h(4)=5$

Hence, we get that,

$h(1)=1$

$h(4)=5$

Answer 2

H(1)= (1)^3= 1
  H(4) =5