To calculate the number of years that the population of the town had been growing we proceed as follows;
A=p(1+r/100)^n
where;
A=final population
p=initial population
n=time
r=rate;
thus, substituting the values in the above formula we get:
28000=20000(1+15/100)^n
1.4=(1+0.15)^n
1.4=1.15^n
introducing natural logs we get:
ln1.4=nln1.15
n=(ln1.4)/(ln1.15)
n=2.4
thus;
n=2.4 years
Answer:
(-5,-5)
Step-by-step explanation:
You would take the 3 and move it over 8 spots on a graph which would place you at (-5,-5)
Answer:
<h2>Earing is $13</h2><h2>Necklace is $10</h2>
Step-by-step explanation:
Firstly, let us express the cost
for Li
5e+n=63---------1
for Jen
e+2n=36---------2
the system of equations are
5e+n=63----1
e+2n=36-----2
Multiply 1 by 1 and 2 by 5 to eliminate e we have
5e+n=63
5e+10n=180
-0-9n=-117
9n=117
Divide both sides by 9 we have
n=117/9
n=13
put n=13 in eqn 1 we have
e+2(13)=36
e+26=36
e=36-26
e=10
Earing is $13
Necklace is $10
15/2 = $7.5 per hour
7.5 times 5 = $37.50 earned in 5 hours