Answer:
Step-by-step explanation:
Let's find a particular solution. We need a function of the form 
such that
and
then, 3a= 8, 2b+6a =0 and c+2b = 0. With the first equation we obtain
a = 8/3 and replacing in the second equation 2b+6(8/3) = 2b + 16 = 0. Then, b = -8. Finally, c = -2(-8) = 16.
So, our particular solution is 
.
Now, let's find the solution 
of the homogeneus equation 
with the method of constants coefficients. Let 
then 
and 
.
So, 
and the solution is
.
Answer:
It has to be A because its the only one that makes sense
Step-by-step explanation:
Answer:
df
Step-by-step explanation:
ff
Answer:
8 one-dollar bills
3 five-dollar bills
2 ten-dollar bills
Step-by-step explanation:
Let x = # of one-dollar bills, y = # of five-dollar bills, and z = # of ten-dollar bills. Total amount in the wallet is $43, so the first equation would be 1x + 5y + 10z = 43. Next, there are 4 times as many one-dollar bills as ten-dollar bills, so x = 4z. There are 13 bills in total, so x + y + z = 13
x + 5y + 10z = 43
x = 4z
x + y + z = 13
x + 5y + 10z = 43
x + 0y - 4z = 0
x + y + z = 13
5y + 14z = 43
-y - 5z = -13
5y + 14z = 43
-5y - 25z = -65
-11z = -22
z = 2
x = 4z
x = 4*2 = 8
x + y + z = 13
8 + y + 2 = 13
10 + y = 13
y = 3
