Answer:2.14.07
Step-by-step explanation:
Answer:
99% Confidence interval: (1196,1973)
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 20
Mean, μ = 1584
Standard Deviation, σ = 607
99% Confidence interval:
Putting the values, we get,

Thus, there is a 99% chance that it will break in approximately 1196 to 1972
Dimensions of the rectangular prism: a=1/2 inches, b=2 inches, c=7/2 inchesVolumen of the rectangular prism: Vr=abcVr=(1/2 inches)(2 inches)(7/2 inches)Vr=[ (1*2*7) / (2*2) ] inches^3Vr=14/4 inches^3Vr=7/2 inches^3
Side of the cube: s=1 incheVolume of the cube: Vc=s^3Vc=(1 inche)^3Vc=1 inche^3
Number of cubes will fit into the rectangular prism: nn=Vr/Vcn=(7/2 inches^3) / (1 inche^3)n=7/2n=3.5
3.5 cubes with side lengths of 1 inche will fit into the prism
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4(4) + 7(3) + 3(4) - 2(3)
(16 + 21) + (12 - 6)
37 + 6
43
Your answer is B. 43
490.87 i think
A= piR^2=pi x 12.5 (the radius) and that roughly equals 490.87385