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mina [271]
3 years ago
14

If g(x) = 3(x − 2), find the value of x if g(x) = 6. A- 12 B- 2.6 C- 8 D -4

Mathematics
1 answer:
Serhud [2]3 years ago
3 0
6=3(x-2)
2=x-2
2+2=x
4=x

Answer is d- 4
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Please help!!!! Use the graph to complete the statement. O is the origin. Ry−axis ο Ry=x: (-1,2)
Fiesta28 [93]

Answer:  D. (-2, -1)

Step-by-step explanation:

Here we do two reflections to the point (-1, 2).

First, we do a reflection over the line x = y.  Remember that a reflection over a line keeps constant the distance between our point and the given line, so we have that for a pint (x, y), the reflection over the line y = x is:

Ry=x (x, y) = (y, x)

so for our point, we have:

Ry=x (-1, 2) = (2, -1)

Now we do a reflection over the y-axis, again, a reflection over a line keeps constant the distance between our point and the given line, so if we have a point (x,y) and we do a reflection over the y-axis, our new point will be:

Ry-axis (x,y) = (-x, y)

Then in our case:

Ry-axis (2, -1) = (-2, -1)

The correct option is D.

5 0
3 years ago
Instert commas to show periods according to the Indian as well as International place value system number of 8888888
natulia [17]

Answer:

88,88,888

Step-by-step explanation:

7 0
3 years ago
Help!! Solving absolute value inequalities
goblinko [34]

Answer:

48. x \geq -7 or x \leq 31

51. x \leq 13 or x \geq 3

54. x < \frac{5}{2} or x > \frac{-15}{2}

57. x < \frac{18}{7} or x > -4

Step-by-step explanation:

48. | 12 - x | \leq 19

-There are two equations:

Equation 1:

12 - x \leq 19

      or

Equation 2:

12 - x \geq -19

Solving equation 1:

12 - x \leq 19

12- 12 - x \leq 19 - 12

-x \leq 7

\frac{-x}{-1} \leq \frac{7}{-1}

x \geq -7 (Inequality sign changed, because of dividing by a negative number)

-Solving equation 2:

12 - x \geq -19

12 - 12  - x \geq -19 - 12

-x \geq -31

\frac{-x}{-1} \geq \frac{-31}{-1}

x \leq 31 (Inequality sign changed, because of dividing by a negative number)

-Answers:

x \geq -7 or x \leq 31

51. | x - 8 | \leq 5

-There are two equations:

Equation 1:

x - 8 \leq 5

    or

Equation 2:

x - 8 \geq - 5

-Solving equation 1:

x - 8 \leq 5

x - 8 + 8 \leq 5 + 8

x \leq 13

-Solving equation 2:

x - 8 \geq - 5

x - 8 + 8 \geq - 5 + 8

x \geq 3

Answers:

x \leq 13 or x \geq 3

54. | 4x + 10 | < 20

-There are two equations:

Equation 1:

4x + 10 < 20

     or

Equation 2:

4x + 10 > -20

-Solving equation 1:

4x + 10 < 20

4x + 10 - 10 < 20 - 10

4x < 10

\frac{4x}{4} < \frac{10}{4}

x < \frac{5}{2}

-Solving equation 2:

4x + 10 > -20

4x + 10 - 10 > -20 - 10

4x > -30

\frac{4x}{4} > \frac{-30}{4}

x > \frac{-15}{2}

-Answers:

x < \frac{5}{2} or x > \frac{-15}{2}

57. | 7x + 5 | < 23

-There are two equations:

Equation 1:

7x + 5 < 23

     or

Equation 2:

7x + 5 > -23

-Solving equation 1:

7x + 5 < 23

7x + 5 - 5 < 23 - 5

7x < 18

\frac{7x}{7} < \frac{18}{7}

x < \frac{18}{7}

Solving equation 2:

7x + 5 > -23

7x + 5 - 5  > -23 - 5

7x > -28

\frac{7x}{7} > \frac{-28}{7}

x > -4

Answers:

x < \frac{18}{7} or x > -4

And we are finished.

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5 0
3 years ago
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Vsevolod [243]
S and N are the variables
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3 years ago
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