Answer:
idk the first 2 but the 3rd one is QR and QT
Step-by-step explanation:
those are the lines on either side of 1.
Let x = # of tickets sold in advance
Let y = # of tickets sold the day of
Cost of the tickets & total sales: 6x & 10y = 6828
You also know y = x + 206
Take the equation mentioned above y = x + 206 and sub it in anywhere the variable y is in the other equations so you'll have this:
6x + 10(x+206) = 6828
Now solve for x to get x = 298
To finish the problem, you must now find the number of y tickets sold.
Sub your x value that you found back into the equation y = x + 206 and you'll get y = 504.
So, 298 tickets were sold in advance and 504 tickets were sold the day of
Answer:
I would say that it is all of them besides the 35% of the participants do not like to surf.
360 - 47 = 313
The answer is A
Answer:
Well u would multiply 20 x 15 to find out the highest if the range which is 300 . So that knocks it down to B or D. But since they're $15 each, It would be based of the multiples of 15 making your answer B .
The range is all the y values.....or the f(x) values .
So the practical range would be the multiples of 15 between 0 and 300,Inclusive .
<h2>Hope this helps you!! </h2>
