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barxatty [35]
4 years ago
5

Writing radicals as a rational exponent ​

Mathematics
1 answer:
Vladimir79 [104]4 years ago
8 0

Lets say you have \sqrt[n]{x}. To write it using a rational exponent, you would write x^{\frac{1}{n}}.

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Please help ! this stuff is so hard ​
Alecsey [184]

Answer:

72 degrees

Step-by-step explanation:

180-45-63=72

4 0
3 years ago
Read 2 more answers
Ana ha comprado libros, todos del mismo precio, por valor de 120 euros. El librero le regala 3 libros por lo que cada libro le c
lidiya [134]

Answer:

El primer paso será darle un nombre a nuestras variables:

x= Numero de libros comprados inicialmente

y=Precio inicial de los libros

Ahora analizamos el enunciado,

Lorena ha comprado libros todos del mismo precio por valor de 120 €

x*y=120 € (1)

El librero le regala 3 libros por lo que en realidad cada libro que cuesta 2 € menos

(x+3)(y-2)=120€ (2)

Tenemos entonces dos ecuaciones con dos incógnitas, así que podemos resolver,

Despejamos en (1)

x=120/y

Sustituimos en (2)

(120/y +3)(y-2)=120

120 - 240/y + 3y -6 =120

3y-240/y =120-120+6

3y -240/y =6

y- 80/y=6

y²-80=6y

y²-6y-80=0

Resolvemos la ecuación de segundo grado

a=1

b=-6

c=-80

Aplicando la resolvente,

(6+- √36+320)/2

6+-√356/2

(6+-18,86)/2

Como el valor de y no puede ser negativo la unica respuesta válida será:

y=12,43

Cada libro le costo 12,43€

Sustituyendo en (1)

x=120/12,43

x=9,65 como no puede ser un número racional

x=9

Lorena ha comprado 9 libros

6 0
3 years ago
X2 + y2 + 4x – 2y = < a
sveticcg [70]

Answer:

a. 2

Step-by-step explanation:

6 0
3 years ago
The sum of two consecutive integers is – 57. Find the two integers.
aliina [53]

Answer:

the integers are -28 and -29

Step-by-step explanation:

Lets do math:

When i was little this was hard but now its pretty easy

look two consecutive numbers are like 1, 2, 3, their difference is usually 1

our equation looks like this:

-57=x+(x-1)

we add 1 to both sides and get:

-56=2x

divide by 2 because im smart

-28=x

thats one number but how 'bout the other one?

we just have to subtract 1 and get -29

the end.

3 0
3 years ago
The least common multiple of a number n and 6 is 42 what are all of the possible whole number values for n
iren [92.7K]
I did it with "tries & mistakes" method:

n is not 1, because LCM of 1 and 6 is 6
n is not 2, because LCM of 2 and 6 is 6
n is not 3, because LCM of 3 and 6 is 6
n is not 4, because LCM of 4 and 6 is 12
n is not 5, because LCM of 5 and 6 is 30
n is not 6, because LCM of 6 and 6 is 6
n might be <u>7</u>, because LCM of 7 and 6 is what we're looking for - 42.
n might be also <u>14</u> or <u>21</u> - so these are all multiplies of 7 which are less or equal to half of 42.

I hope it helps :)
5 0
3 years ago
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