So I'm going to assume that this question is asking for <u>non extraneous solutions</u>, or solutions that are found in the equation <em>and</em> are valid solutions when plugged back into the equation. So firstly, subtract 2 on both sides of the equation:

Next, square both sides:

Next, subtract x and add 2 to both sides of the equation:

Now we are going to be factoring by grouping to find the solution(s). Firstly, what two terms have a product of 6x^2 and a sum of -5x? That would be -3x and -2x. Replace -5x with -2x - 3x:

Next, factor x^2 - 2x and -3x + 6 separately. Make sure that they have the same quantity on the inside of the parentheses:

Now you can rewrite the equation as 
Now, apply the Zero Product Property and solve for x as such:

Now, it may appear that the answer is C, however we need to plug the numbers back into the original equation to see if they are true as such:

Since both solutions hold true when x = 2 and x = 3, <u>your answer is C. x = 2 or x = 3.</u>
Answer:
Yes a 1:3 ratio
Step-by-step explanation:
Yes triangle A is 3 times bigger than triangle B. So it takes 3 B triangles to make one A triangle.
Answer:
$24
Step-by-step explanation:
1/4x + 1/3x + 8 = 22
1/4x + 1/3x = 7/12x
7/12x + 8 = 22
22 - 8 = 14
7/12x = 14
14/ 7/12
x = 24
Answer: (–3, 1) , (5, –2)
Step-by-step explanation: Got it right Edgenuity