Question

QUALITY CONTROL1)Specifications for a part for a DVD player state that the part should weigh between 24.6 and 25.6 ounces. The process that produces the parts has a mean of 25.1 ounces and a standard deviation of .26 ounce. The distribution of output is normal. a)What control chart will you use and why?b)With a 2-sigma confidence, what are the upper and lower control limitsif sample of n = 11are taken and the process is in control (random)?c)Is the process in control

Answer 1

Answer:

Step-by-step explanation:

Given that,

μ = 25.1

σ = 0.26

a) since standard deviation is ideal measure of dispersion , a combination of control chart for mean x and standard deviation known as

$\bar x \\\text {and}\\\mu$

Chart is more appropriate than $\bar x$ and R - chart for controlling process average and variability

so we use

$\bar x \\\text {and}\\\mu$charts

b)

n = 11

we have use 2 σ confidence

so, control unit for $\bar x$ chart are

upper control limit  = $\mu +2\times\frac{ \sigma}{\sqrt{n} }$

lower control limit = $\mu -2\times\frac{ \sigma}{\sqrt{n} }$

control limit = μ

μ = 25.1

upper control limit  =

$25.1+2\times \frac{0.26}{\sqrt{11} } \\\\=25.2567$

lower control limit =

$25.1-2\times \frac{0.26}{\sqrt{11} } \\\\=24.9432$

Upper control limit and lower control limit are in between the specification limits , that is in between 24.9 and 25.6

so, process is in control

c) if we use 3 sigma limit with n = 11

then

upper control limit  = $\mu +3\times\frac{ \sigma}{\sqrt{n} }$

$25.1+3\times\frac{0.26}{\sqrt{11} } \\\\=25.3351$

lower control limit  = $\mu -2\times\frac{ \sigma}{\sqrt{n} }$

$25.1-3\times\frac{0.26}{\sqrt{11} } \\\\=24.8648$

control limit is 25.1

Then, process is in control since upper control limit and lower control limit lies between specification limit

So, process is in control