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2 years ago

Simplify (x2 + 7x + 12)(x2 + 3x + 5).

1 answer:

8 0

Hi there

(x² + 7x + 12)(x² + 3x + 5)
Distribute
(x²)(x²) + (x²)(3x) + (x²)(5) + (7x)(x²) + (7x)(3x) + (7x)(5) + (12)(x²) + (12)(3x) + (12)(5)
= x^4 + 3x^3 + 5x^2 + 7x^3 + 21x^2 + 35x + 12x^2 + 36x + 60
= x^4 + 10x^3 + 38x^2 + 71x + 60

Good luck !

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Given a line segment that contains the points A,B, & C in order, if AB = x, BC = x, and AC is equal to 36, then x = _____.

Bumek [7]

Answer:

a. 18

Step-by-step explanation:

AB+BC = AC

x + x = 36

2x = 36

x = 36/2

x = 18

6 0

3 years ago

Can someone help me with this problem

Alex_Xolod [135]

Answer:

Step-by-step explanation:

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

A(-3, 0) , B(3, 2)

$AB=\sqrt{(3-(-3))^2+(2-0)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=\sqrt{4\cdot10}=\sqrt4\cdot\sqrt{10}=2\sqrt{10}$

A(-3, 0), D(-2, -3)

$AD=\sqrt{(-2-(-3))^2+(-3-0)^2}=\sqrt{1^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

AB = CD and AD = BC

The area of a rectangle:

$A=(AB)(AD)$

Substitute:

$A=(2\sqrt{10})(\sqrt{10})=(2)(10)=20$

The perimeter of a rectangle:

$P=2(AB+AD)$

Substitute:

$P=2(2\sqrt{10}+\sqrt{10})=2(3\sqrt{10})=6\sqrt{10}$

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3 years ago

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Troyanec [42]

The answer is 35.

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3 years ago

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Answer:

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2 years ago