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saveliy_v [14]
3 years ago
9

Possible grades for a class are A, B, C, D, and F. (No +/− 's.) How many ways are there to assign grades to a class of seven stu

dents?
Mathematics
1 answer:
Archy [21]3 years ago
8 0

Answer: 78125 ways

Step-by-step explanation:

Given : The number of possible grades = 5

The number of students in the class = 7

Then, the number of ways  to assign grades to a class of seven students :_

5\times 5\times 5\times 5\times 5\times 5\times 5=5^7=78125

Hence, there are 78125 ways to assign grades to a class of seven students .

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Solve the absolute value equation. If no solution write NO SOLUTION.<br> -{2x + 3] + 8<br> 12
Natasha2012 [34]

Answer:

If problem is "-|2x+3|+8=12"

then there is (<em>no solution.)</em>

Step-by-step explanation:

Let's solve your equation step-by-step.

−|2x+3|+8=12

Step 1: Add -8 to both sides.

−|2x+3|+8+−8=12+−8

−|2x+3|=4

Step 2: Divide both sides by -1.

−|2x+3|=4

   -1       -1

|2x+3|=−4

Step 3: Solve Absolute Value.

|2x+3|=−4

No solutions Because absolute value is less than 0.

4 0
3 years ago
A journal article reports that a sample of size 5 was used as a basis for calculating a 95% CI for the true average natural freq
oksano4ka [1.4K]

Answer:

Lower = 231.134- 3.098=228.036

Upper = 231.134+ 3.098=234.232

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n=5 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case we know that the 95% confidence interval is given by:

\bar X=\frac{233.002 +229.266}{2}= 231.134

And the margin of error is given by:

ME = \frac{233.002 -229.266}{2}= 1.868

And the margin of error is given by:

ME= t_{\alpha/2} \frac{s}{\sqrt{n}}

The degrees of freedom are given by:

df = n-1 = 5-1=4

And the critical value for 95% of confidence is t_{\alpha/2}= 2.776

So then we can find the deviation like this:

s = \frac{ME \sqrt{n}}{t_{\alpha/2}}

s = \frac{1.868* \sqrt{5}}{2.776}= 1.506

And for the 99% confidence the critical value is: t_{\alpha/2}= 4.604

And the margin of error would be:

ME = 4.604 *\frac{1.506}{\sqrt{5}}= 3.098

And the interval is given by:

Lower = 231.134- 3.098=228.036

Upper = 231.134+ 3.098=234.232

6 0
3 years ago
Find the rate and unit rate:
Alenkinab [10]



A: 24 miles per 1 gallon
5 0
3 years ago
Read 2 more answers
If Jane's shirt cost 20$, but she has a 15% off coupon, what is her cost before tax
alina1380 [7]

Answer:

17

Step-by-step explanation:

The discount on the shirt is 15%

Discount = price* discount rate

               = 20 * 15%

               = 20 * .15

                =3

The new price is the previous price minus the discount

new price = 20-3

new price = 17

8 0
3 years ago
Read 2 more answers
What is the simplified form?
MAVERICK [17]

Answer:

A fraction is in simplest form when the top and bottom cannot be any smaller, while still being whole numbers.

Step-by-step explanation:

6 0
3 years ago
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