Answer:
Step-by-step explanation:
<u>1- digit numbers: </u>
- 1 to 9, number of digits = 9
<u>2- digit numbers:</u>
- 10 to 99, number of digits = 2(99 - 9) = 180
<u>3- digit numbers:</u>
- 100 to 999, number of digits = 3(999 - 99) = 2700
This is more than we have, but we know the number of pages is 3-digit.
<u>Let it be x, then we have:</u>
- 9 + 180 + 3(x - 99) = 1074
- 3(x - 99) = 1074 - 189
- 3(x - 99) = 885
- x - 99 = 885/3
- x - 99 = 295
- x = 295 + 99
- x = 394
V=3.14*4/3*r^3
r=4/2=2
v=3.14*4/3*2^3=33.4933333
B
Answer:B
Step-by-step explanation:
Took the test
Answer:
Step-by-step explanation:
a: Wrong. The first thing that you have to notice is that the sum goes to infinity. If you want k=4 to be the last condition, then take out the 3 dots.
b: That's the answer.
c: wrong. You get a real mess when you let set k = 0. Try it on your calculator.
1 ÷ 0 = Watch carefully as your calculator mentally melts down.
d: wrong. It's just not right. The highest power is k^2. There is no way to get k^3
Backing out the bonus, we get 2711 - 250 = 2461, which is 161 more than his last check
<span>So 161 / 2300 = 0.07, or 7%</span>
