Find the inertia tensor for an equilateral triangle in the xy plane. Take the mass of the triangle to be M and the length of a side of the triangle to be b. Express your answer below as pure numbers in units of Mb^2. Place the origin on the midpoint of one side and set the y-axis to be along the symmetry axis.
The sides of the right-angle triangle will be 16 units and 20.30 units. And the missing angle will be 52°.
<h3>What is a right-angle triangle?</h3>
It's a form of a triangle with one 90-degree angle that follows Pythagoras' theorem and can be solved using the trigonometry function.
The side AC will be
tan 38° = 12.5 / AC
AC = 15.999
AC ≈ 16 units
Then the side AB will be
AB² = 12.5² + 16²
AB = 20.30 units
We know that the angle sum is 180 degrees. Then we have
∠A + ∠B + ∠C = 180°
38° + ∠B + 90° = 180°
∠B = 52°
More about the right-angle triangle link is given below.
brainly.com/question/3770177
#SPJ1
Step-by-step explanation:
3(-8m-1) + 5(m+8) (remove the parentheses)
-24m - 3 + 5m + 40 (collect like terms and calculate)
-19m + 37