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Virty [35]
3 years ago
13

Algebraic expression and identity 1)simplify the following (3a+b)3 +(3a-b)3

Mathematics
1 answer:
mylen [45]3 years ago
5 0

Answer:

(3a+b)^3+(3a-b)^3=54a^3+18ab^2

Step-by-step explanation:

Given: (3a+b)^3+(3a-b)^3

Formula: x^3+y^3=(x+y)(x^2-xy+y^2)

(x+y)^2=x^2+2xy+y^2

(x-y)^2=x^2-2xy+y^2

x\rightarrow 3a+b

y\rightarrow 3a-b

\Rightarrow (3a+b+3a-b)((3a+b)^2-(3a+b)(3a-b)+(3a-b)^2)

\Rightarrow (6a)(9a^2+b^2+6ab-9a^2+b^2+9a^2+b^2-6ab)

\Rightarrow (6a)(9a^2+3b^2)

\Rightarrow 54a^3+18ab^2

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Factor the expression 45b+40​
natali 33 [55]

Answer:

5(9b + 8)

Step-by-step explanation:

Rewrite 45 as 5 * 9

Rewrite 40 as 5 * 8

= 5 * 9b + 5 * 8

Factor out common term 5

=5 (9b + 8)

6 0
2 years ago
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melisa1 [442]

Answer:

  • Yes, No, Yes

Step-by-step explanation:

<u>Use the Pythagorean theorem:</u>

  • a² + b² = c²

<u>Verify this for each line:</u>

1.

  • 28² + 45² = 53²
  • 2809 = 2809
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2.

  • 33² + 56² = 64²
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3.

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5 0
2 years ago
A parabola can be drawn given a focus of (5, -3) and a directrix of y=1. Write the equation of the parabola in any form.
Anna71 [15]

Answer:

(x²-10x+33)/(-8) = y

Step-by-step explanation:

The distance between any point on a parabola from both its focus and directrix are the same.

Let's say we have a point (x,y) on the parabola. We can then say that using the distance formula,

\sqrt{(x-5)^2+(y-(-3))^2}is the distance between (x,y) and the focus. Similarly, the distance between (x,y) and the directrix is |y-1| (I use absolute value here because distance is always positive). We can find this equation by taking the shortest distance from the point to the line. Because the closest point to the line will be the same x value as the point itself, the distance is simply the distance between the y value of the point and the y value of the directrix.

Equating the two equations given, we have

\sqrt{(x-5)^2+(y-(-3))^2} = |y-1|

square both sides to get

(x-5)²+(y+3)²=(y-1)²

expand the y components

(x-5)² + y²+6y+9 = y²-2y+1

subtract y²+6y+9 from both sides

(x-5)² = -8y - 8

expand the x components

x²-10x+25 = -8y - 8

add 8 to both sides to isolate the -8y

x²-10x+33 = -8y

divide both sides by -8 to isolate y

(x²-10x+33)/(-8) = y

6 0
2 years ago
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Answer:

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