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3 years ago

8

Please help me with this question

1 answer:

wel3 years ago

4 0

If I could get more context then that would help. Because an exponent being an odd number doesn’t do anything, so it could be either a negative or a positive

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Find the sizes of the angles marked with a letter.<br> Why is my answer wrong?

jeyben [28]

Answer:

29.28 degrees.

Step-by-step explanation:

sin x / 16.2 = sin 49 / 25

Cross multiply:

25 sin x = 16.2 * sin 49

sin x = (16.2 * sin 49) / 25

sin x = 0.48905

x = 29.28 degrees.

8 0

4 years ago

What is the test that you can do to tell if a graph represents a function?

LenKa [72]

B. the vertical line test

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3 years ago

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In the sequence 80, 64, 48, 32, ..., what number should come next?

otez555 [7]

(b) sixteen is the answer

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3 years ago

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A right circular cylinder is inscribed in a sphere with diameter 4cm as shown. If the cylinder is open at both ends, find the la

SOVA2 [1]

Answer:

$8\pi\text{ square cm}$

Step-by-step explanation:

Since, we know that,

The surface area of a cylinder having both ends in both sides,

$S=2\pi rh$

Where,

r = radius,

h = height,

Given,

Diameter of the sphere = 4 cm,

So, by using Pythagoras theorem,

$4^2 = (2r)^2 + h^2$ ( see in the below diagram ),

$16 = 4r^2 + h^2$

$16 - 4r^2 = h^2$

$\implies h=\sqrt{16-4r^2}$

Thus, the surface area of the cylinder,

$S=2\pi r(\sqrt{16-4r^2})$

Differentiating with respect to r,

$\frac{dS}{dr}=2\pi(r\times \frac{1}{2\sqrt{16-4r^2}}\times -8r + \sqrt{16-4r^2})$

$=2\pi(\frac{-4r^2+16-4r^2}{\sqrt{16-4r^2}})$

$=2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})$

Again differentiating with respect to r,

$\frac{d^2S}{dt^2}=2\pi(\frac{\sqrt{16-4r^2}\times -16r + (-8r^2+16)\times \frac{1}{2\sqrt{16-4r^2}}\times -8r}{16-4r^2})$

For maximum or minimum,

$\frac{dS}{dt}=0$

$2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})=0$

$-8r^2 + 16 = 0$

$8r^2 = 16$

$r^2 = 2$

$\implies r = \sqrt{2}$

Since, for r = √2,

$\frac{d^2S}{dt^2}=negative$

Hence, the surface area is maximum if r = √2,

And, maximum surface area,

$S = 2\pi (\sqrt{2})(\sqrt{16-8})$

$=2\pi (\sqrt{2})(\sqrt{8})$

$=2\pi \sqrt{16}$

$=8\pi\text{ square cm}$

4 0

3 years ago

Dau coroana <br> daca il faceti

Andre45 [30]

Answer:

I give the crown

if you do

Step-by-step explanation:

6 0

3 years ago

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