Hi there!
200(20)^x > 500x + 400
Let's find the critical points of the inequality
200(20^x) = 500x + 400
Now we can divide both sides by 200
(200(20^x))/200 = (500x + 400)/200
20x^x = 5/2 x + 2
There are no critical points.
Thus,
The answer is: No solution
As always, it is my pleasure to help students like you.
The slope is -2/3.
You have to do -2-2 and you get -4.
Then you do 12-6 and you get 6.
The final step is to do -4 divide 6 and you get -2/3.
Answer:
1.x^7
2.x^10
3.a^2
4. 5
Step-by-step explanation:
1. x^(5+2)=x^7
2.x^(5*2)=x^10
3.a^(5-3)=a^2
4. 5 * 1=5
the decimals are commas and the double decimal is a real decimal
We have been given a graph of piecewise function. Using that we have to select the function from given choices which is represented by graph.
g(x) = −2x, −2 < x < 0
Answer:
NO. Because g(x) = −2x has negtive slope so that means it goes downward also there is no y-intercept in g(x) = −2x but the only graph that has y-intercept in given graph goes upwawrd so that can't be answer.
g(x) = −2, x < −2
Answer:
YES. Because g(x) = −2 is a horizontal line which is only on the left side oof x=-2. Graph of this part is present in given graph. So yes it is answer.
g(x) = x − 2, −2 < x < 1
Answer:
NO. Because g(x) = x−2 has y-intercept at y=-2 and slope 1 so that means graph of g(x)= x-2 must be going upward and crossing at y=-2 butt there is no such graph. Hence this can't be answer.
g(x) = −2x + 6, x ≥ 1
Answer:
YES. Because g(x) = −2x+6 satisfies the graph which is going downward.
g(x) = x/2+ 1, –2 ≤ x < 1
Answer:
YES. Because g(x) = x/2+ 1 satisfies the graph which is going downward.
