.49027397189 out of 365 is what?<br> 12 POINTS

Does anyone know this i need an answer asap btw its 8th grade work

vesna_86 [32]

Quadrilateral 2 will be parallel just like the first Quadrilateral. The shapes are the same and AD and BC are parallel on both shapes.

6 0

4 years ago

Which expressions below are equivalent to –3(0.15 – 0.2 + 0.25p) ? Please help, thanks 0.15 – 0.75p –0.45 – 0.6 + 0.75p –3(–0.05

user100 [1]

Given:

The expression is

$-3(0.15-0.2+0.25p)$

To find:

The equivalent expression.

Solution:

We have,

$-3(0.15-0.2+0.25p)$

It can be written as

$=-3(-0.05+0.25p)$

So, option C is correct.

$=-3(-0.05)+(-3)(0.25p)$

$=0.15-0.75p$

So, option A is correct.

The given expression can be written as

$=-3(0.15)+(-3)(-0.2)+(-3)(0.25p)$

So, option D is incorrect.

$=-0.45+0.6-0.75p$

So, option B is incorrect.

Therefore, the correct options are A and C.

4 0

3 years ago

How do I simplify the expression

stiks02 [169]

ANSWER: ab√3ac

Is this enough for you ?

5 0

3 years ago

Dina and Masha start cycling on a 20 km bike path at the same time. When Dina reaches the end of the path, Masha still has 4 km

sammy [17]

Answer:

0.5 hour

Step-by-step explanation:

Given

Speed of Dina = 10 km/h

Distance = 20 km

So the time Dina taken to complete the track is:

$Speed=\frac{distance}{time}\\10=\frac{20}{time}\\time=\frac{20}{10}\\ time=2\ hours$

The time taken by Dina is 2 hours. As masha started with dina but she was 4 km of the path left to cycle,

her distance covered in 2 hours was:

$Distance\ covered\ by\ Masha\ in\ 2\ hours=20-4\\=16 km$

So we know the time and distance:

Now,

$Speed\ of\ Masha=\frac{distance}{time}\\ =\frac{16}{2}\\ =8\ kilometer\ per\ hour$

We have to calculate the time that will be needed by MAsha to complete the track:

As we know the speed and remaining distance

$Speed=\frac{distance}{time}\\8=\frac{4}{time}\\ time=\frac{4}{8}\\time=0.5\ hours$

Masha needs 0.5 hour to complete the track ..

7 0

3 years ago

Read 2 more answers

A scientist inoculates mice, one at a time, with a disease germ until he finds 2 that have contracted the disease. if the probab

AnnyKZ [126]

<span>There are several possible events that lead to the eighth mouse tested being the second mouse poisoned. There must be only a single mouse poisoned before the eighth is tested, but this first poisoning could occur with the first, second, third, fourth, fifth, sixth, or seventh mouse. Thus there are seven events that describe the scenario we are concerned with. With each event, we want two particular mice to become diseased (1/6 chance) and the remaining six mice to remain undiseased (5/6 chance). Thus, for each of the seven events, the probability of this event occurring among all events is (1/6)^2(5/6)^6. Since there are seven of these events which are mutually exclusive, we sum the probabilities: our desired probability is 7(1/6)^2(5/6)^6 = (7*5^6)/(6^8).</span>

5 0

3 years ago

.49027397189 out of 365 is what? 12 POINTS