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poizon [28]
3 years ago
13

.49027397189 out of 365 is what? 12 POINTS

Mathematics
1 answer:
erastova [34]3 years ago
4 0
The answer would be

744.4816998808433                      
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Find the net pay hours worked 27 1/4 5.15 an hour
natali 33 [55]

$440.34 because 27 1/4 X 5.15 = $440.3375 rounded to nearest hundredth $440.34

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3 years ago
Between which two consecutive integers does <img src="https://tex.z-dn.net/?f=%5Csqrt%7B%7D%2012%5C%5C" id="TexFormula1" title="
Annette [7]

The most appropriate choice for square root will be given by-

\sqrt{12} lies between 3 and 4

What is square root of a number?

Number raised to the power \frac{1}{2} is the square root of  the number.

Here

\sqrt{12}\\ 2\sqrt{3}\\ 2*1.732\\3.464\\

3.464 lies between 3 and 4

\sqrt{12} lies between 3 and 4

To learn more about square root of a number, refer to the link:

brainly.com/question/3617398

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7 0
1 year ago
consider these graphs: Eric thinks the equation y=(x-3)^2 will match the blue graph. Jenney thinks it will match the red graph.
Dimas [21]

Answer: Jenny

Step-by-step explanation:

By subtitue Y = 0

0=(x-3)^2

And you get 3

3 0
3 years ago
HELP! WILL GIVE BRAINLIEST
likoan [24]

Answer: area 24 perimeter/circumstance 32 meters

Step-by-step explanation:

3 0
3 years ago
An article describes a study comparing two methods of measuring mean arterial blood pressure. The auscultatory method is based o
zzz [600]

Answer:

p_v =P(t_{(5)}>0.499) =0.319

The p value is higher than any significance level given for example \alpha=0.05,0.1, so then we can conclude that we FAIL to reject the null hypothesis. So we don't have enough evidence to conclude that the mean reading is greater for the auscultatory method at 5% or 10% of significance.

Step-by-step explanation:

A paired t-test is used to compare two population means where you have two samples in  which observations in one sample can be paired with observations in the other sample. For example  if we have Before-and-after observations we can use it.  

Let put some notation  

x=Auscultatory method , y = Oscillatory method

x: 74 86 84 79 70 78 79 70

y: 70 85 90 110 71 80 69 74

The system of hypothesis for this case are:

Null hypothesis: \mu_x- \mu_y \leq 0

Alternative hypothesis: \mu_x -\mu_y >0

The first step is define the difference d_i=x_i-y_i, that is given so we have:

d: 6.6, 4.2, -5.5, -3.1, 9.3, -3.9

The second step is calculate the mean difference  

\bar d= \frac{\sum_{i=1}^n d_i}{n}=1.267

The third step would be calculate the standard deviation for the differences, and we got:

s_d =\sqrt{\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1}} =6.215

The fourth step is calculate the statistic given by :

t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{1.267 -0}{\frac{6.215}{\sqrt{6}}}=0.499

The next step is calculate the degrees of freedom given by:

df=n-1=6-1=5

Now we can calculate the p value, since we have a right tailed test the p value is given by:

p_v =P(t_{(5)}>0.499) =0.319

The p value is higher than any significance level given for example \alpha=0.05,0.1, so then we can conclude that we FAIL to reject the null hypothesis. So we don't have enough evidence to conclude that the mean reading is greater for the auscultatory method at 5% or 10% of significance.

5 0
3 years ago
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