Answer:
y=1/2x+5
Step-by-step explanation:
Plug it into the formula for a point and a slope.
(y-(y(subscript 1)))=(m)(x-(x(subscript 1)))
Y-8=1/2(x-6)
Then multiply the 1/2 to the x and -6. After you do that, move everything so that it has y by itself on the left. Your ending should be y=1/2x+5.
If the circumference is half of the perimeter than the area for both circles would be half of them find one circles area and half it
Check picture below, solve for "x" and "y"
unless you've already covered the 30-60-90 triangle, then check your book on them, to see the ratios, using the 30-60-90 ratios is simpler
Answer:
<h2>The required answer is 218 degree.</h2>
Step-by-step explanation:
∠AOB = 90 degree.
∠BOC = 52 degree.
Arc CDE = 180 degree, since CE is the diameter.
Hence, Arc EAC = 180 degree.
Besides, Arc EAC = Arc EA + Arc AB + Arc BC = Arc EA + 90 + 52 = Arc EA + 142.
Thus, Arc EA = 180 - 142 = 38 degree.
Arc ADC = 180 + 38 = 218 degree.
Answer:
Step-by-step explanation:
coordinate of O(2,1),Y(3,-2),T(-3,-3)
let the reflected points are O',Y',T'
distance of O from y=2 is 1 unit.
∴ ordinate of O' =1+2(1)=3
or O' is (2,3)
distance of Y from y=2 is2+2=4
ordinate of Y'=-2+2(4)=6
so coordinate of Y' is (3,6)
distance of T from y=2 is (2+3)=5
so ordinate of T' =-3+2(5)=7
coordinate of T' is(-3,7)
