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Arte-miy333 [17]
3 years ago
12

your parents are decorating the dining room and want to place two rectangular wall sconce lights that are 25 inches wide along a

10 2/3 foot wall so that the distance between the lights and the distances from each light to the nearest edge of the wall are all the same. Design the wall and determine the distance
Mathematics
1 answer:
taurus [48]3 years ago
6 0
First note that 10 2/3 feet equate 127.2 inches. 
Denote by x the distance we are looking for. 
We have the following equation:
x+25+x+25+x=127.2
Solving the above equation for x we  get:
x=\frac{127.2-25-25}{3}=25.7
The distance is 25.7 inches. 
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The simplest form is 2 with working out shown on photo

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3 years ago
Please answer ASAP<br> Thank you so much!!!!!
Natali5045456 [20]

Answer:

g (f(0)) =   -4.5

Step-by-step explanation:

Find f(0) =   (3(0)-7)/4  = -7/4

   sub this into g(x)

          g(-7/4) = 2 (-7/4) -1 = -14/4   - 4/4 = - 18/4 = -4.5  

7 0
2 years ago
Tim claims that a coin is coming up tails less than half of the time. In 110 tosses, the coin comes up tails 47 times. Using P-v
lilavasa [31]

Answer:

z=\frac{0.427 -0.5}{\sqrt{\frac{0.5(1-0.5)}{110}}}=-1.531  

p_v =P(z  

If we compare the p value obtained and using the significance level given \alpha=0.1 we have that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 10% of significance the proportion of tails is significantly less than 0.5.  

Step-by-step explanation:

1) Data given and notation

n=110 represent the random sample taken

X=47 represent the number of tails obtained

\hat p=\frac{47}{110}=0.427 estimated proportion of tails

p_o=0.5 is the value that we want to test

\alpha=0.1 represent the significance level

Confidence=90% or 0.90

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion of tails is lower than 0.5:  

Null hypothesis:p\geq 0.5  

Alternative hypothesis:p < 0.5  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.427 -0.5}{\sqrt{\frac{0.5(1-0.5)}{110}}}=-1.531  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.1. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(z  

If we compare the p value obtained and using the significance level given \alpha=0.1 we have that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 10% of significance the proportion of tails is significantly less than 0.5.  

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Morgan buys 6 rolls of paper towels. She got 525.6 feet of paper towels in all. How many feet was each roll?
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87.6 is the answer or 88 aproximaded
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