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Olenka [21]
3 years ago
15

Identify an equation in point-slope form for the line perpendicular to

Mathematics
1 answer:
Zigmanuir [339]3 years ago
8 0

Answer:

perp. : 1/3= m

y + 8 = 1/3(x -4): answer is c

y + 24/3 = (1/3)x - 4/3

y = (1/3)x - 28/3

Step-by-step explanation:

answer is c

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Which expressions are equivalent to z + (z + 6)
elixir [45]

Answer:

C  2(z+3)

Step-by-step explanation:

z+(z+6)

Combine like terms

2z+6

We can factor out a 2 from each term

2(z+3)

7 0
3 years ago
During the month of February, fabulous feet shoe mart sold 48 pairs of red loafers. After an ad campaign to boost sales, they so
Anvisha [2.4K]
<span>Sales went from 48 pairs to 60 pairs: total change = 60 - 48 = 12 percentage change = 12 / 48 = 0.25 = 0.25*100% = 25% Answer: 25%</span>
8 0
3 years ago
Read 2 more answers
What is 4x-7xy+9xy-7pq
konstantin123 [22]
Answer:  " 4x + 2xy - 7pq " .
___________________________________
Explanation:
___________________________________
Given:  
" <span>4x - 7xy + 9xy - 7pq " ;  Simplify the expression;
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  Combine the "like terms:
___________________________________
       -7xy + 9xy = 2xy ;
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Now, rerewrite the expression, substituting the "-7xy + 9xy";  with " + 2xy" ;
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   </span>→ " 4x + 2xy - 7pq " .
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4 0
3 years ago
Need help on this please
jenyasd209 [6]

Answer:

Step-by-step explanation:

THIS PIC IS VERY GOOD BUT NOT CLEAR SO I HELP YOU

5 0
3 years ago
I AM GIVING 45 POINTS TO WHOEVER GETS THIS RIGHT... plz answer corectly and try... i was working on this for sooo long. Plz try
Alexxx [7]
When you have 3 choices for each of 6 spins, the number of possible "words" is
  3^6 = 729

The number of permutations of 6 things that are 3 groups of 2 is
  6!/(2!×2!×2!) = 720/8 = 90

A) The probability of a word containing two of each of the letters is 90/729 = 10/81


The number of permutations of 6 things from two groups of different sizes is
  (2 and 4) : 6!/(2!×4!) = 15
  (3 and 3) : 6!/(3!×3!) = 20
  (4 and 2) : 15
  (5 and 1) : 6
  (6 and 0) : 1

B) The number of ways there can be at least 2 "a"s and no "b"s is
  15 + 20 + 15 + 6 + 1 = 57
The probability of a word containing at least 2 "a"s and no "b"s is 57/729 = 19/243.


_____
These numbers were verified by listing all possibilities and actually counting the ones that met your requirements.
6 0
3 years ago
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