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Olenka [21]
3 years ago
15

Identify an equation in point-slope form for the line perpendicular to

Mathematics
1 answer:
Zigmanuir [339]3 years ago
8 0

Answer:

perp. : 1/3= m

y + 8 = 1/3(x -4): answer is c

y + 24/3 = (1/3)x - 4/3

y = (1/3)x - 28/3

Step-by-step explanation:

answer is c

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Sheila is ordering pizzas for a party. Each plain pizza costs $9.00, and each topping costs $1.50. The delivery charge is $3.00.
ivolga24 [154]
F(5)=$63.00 is the correct answer
4 0
3 years ago
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A function for the cost of renting a snow blower is $13.50 per hour.
jekas [21]

1= $13.50

2= $27

3=$40.50

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3 0
3 years ago
Write an equation that has (2, -3) as a solution
xxTIMURxx [149]

Answer:

y=x-5

Step-by-step explanation:

5 0
3 years ago
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1. Determine el valor de W en las proporciones siguientes:<br> a) (12/w) = (4/3); w =
8090 [49]

Aplicando multiplicación cruzada, tiene-se que el valor de w es w = 9.

  • Cuando una proporción es dada, con una igualdade de duas proporciones, puede-se aplicar multiplicación cruzada entre ellas.

En este problema, la ecuación que relaciona las proporciones es dada por:

\frac{12}{w} = \frac{4}{3}

Aplicando multiplicación cruzada:

4w = 12(3)

4w = 36

w = \frac{36}{4}

w = 9

El valor de w es w = 9.

Un problema similar es dado en brainly.com/question/24615636

6 0
2 years ago
It is given 5 and h + 1 are the roots of the quadratic equation x² + (k - 1)x - 5 = 0,where h and k are constant.Find the value
Liono4ka [1.6K]

Answer:

Hello,

<u>k=-3 and h=-2</u>

Step-by-step explanation:

5\ is\ a \ root \of \ x^2+(k-1)*x-5=0\\\\5^2+(k-1)*5-5=0\\\\5*(k-1)+20=0\\\\k-1=\dfrac{-20}{5} \\\\k=-4+1\\\\\boxed{k=-3}\\

h+1 is thus a root of x²+(-3-1)*x-5=0

x²-4x-5=0

x²+x-5x-5=0

x(x+1)-5(x+1)=0

(x+1)(x-5)=0

h+1=-1

<u>h=-2</u>

6 0
3 years ago
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