4 years ago

Let f be the function defined as follows.

1 answer:

4 0

Y = f(x) = 8x^2 - 2x + 3
a.) dy/dx = 16x - 2

b.) dy = (16x - 2)dx
dy = (16(2) - 2)(2 - 1.97) = 0.03(32 - 2) = 0.03 * 30 = 0.9
dy = 0.9

c.) (8(2)^2 - 2(2) + 3) - (8(1.97)^2 - 2(1.97) + 3) = 31 - 30.1072 = 0.8928
Δy = 0.8928

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