Question

What is the value of h when the function is converted to vertex form?

Answer 1

Answer:  The value of 'h' is 3.

Step-by-step explanation:  Given that the vertex form of a function is given by

$g(x)=a(x-h)^2+k~~~~~~~~~~~~~~~~~~~~~~~~(i)$

We are to find the value of 'h' when the following function is converted to the vertex form.

$g(x)=x^2-6x+14~~~~~~~~~~~~~~~~~~~~~~(ii)$

From equation (ii), we have

$g(x)=x^2-6x+14\\\\\Rightarrow g(x)=x^2-2\times x\times 3+3^2-3^2+14\\\\\Rightarrow g(x)=(x-3)^2-9+14\\\\\Rightarrow G(x)=(x-3)^2+5.$

Comparing it with the vertex form (i), we get

$h=3.$

Thus, the value of 'h' is 3.