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just olya [345]
3 years ago
7

How do yu solve log7-2log 12 ?

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
4 0
Log 7 - 2log 12 = log \frac{7}{ 12^{2} } ≈ -1.31
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The weekly incomes of a large group of executives are normally distributed with a mean of $2,000 and a standard deviation of $10
8_murik_8 [283]

Answer:

The z-score for an income of $2,100 is 1.

Step-by-step explanation:

If X \sim N (µ, σ²), then  Z=\frac{x-\mu}{\sigma}, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z \sim N (0, 1).

The distribution of these z-variate is known as the standard normal distribution.

Given:

µ = $2,000

σ = $100

<em>x</em> = $2,100

Compute the <em>z</em>-score for the raw score <em>x</em> = 2100 as follows:

Z=\frac{x-\mu}{\sigma}=\frac{2100-2000}{100}=\frac{100}{100}=1

Thus, the z-score for an income of $2,100 is 1.

4 0
3 years ago
Need help please and thank you
yulyashka [42]

Answer:

no thank you

Step-by-step explanation:

lol good day

6 0
2 years ago
Read 2 more answers
Find the axis of symmetry and the vertex and graph the following: f(x)=(x+2)(x-4)
algol [13]

something noteworthy is that the independent and squared variable in this case will be the "x", namely the graph of that quadratic is a vertical parabola.

\bf f(x) = (x+2)(x-4)\implies 0=(x+2)(x-4)\implies x = \begin{cases} -2\\ 4 \end{cases} \\\\\\ \boxed{-2}\rule[0.35em]{7em}{0.25pt}0\rule[0.35em]{3em}{0.25pt}\stackrel{\downarrow }{1}\rule[0.35em]{10em}{0.25pt}\boxed{4}

so the parabola has solutions at x = -2 and x = 4, and its vertex will be half-way between those two guys, namely at x = 1.

since this is a vertical parabola, its axis of symmetry, the line that splits its into twin sides, will be a vertical line, and it'll be the x-coordinate of the vertex, since the vertex hasa a coordinate of x = 1, then the axis of symmetry is the vertical line of x = 1.

8 0
3 years ago
Fifteen more than z times 6 is 11 less than y times 2
nata0808 [166]
<h3>Given:</h3>

Fifteen more than z times 6 is 11 less than y times 2

<h3>Solution:</h3>

Fifteen more than z times 6 = 6z + 15

11 less than y times 2 = 2y - 11

<h2>Answer:</h2>

6z + 15 = 2y - 11

7 0
3 years ago
A right square pyramid has a slant height of 10 feet, and the length of a side
kotykmax [81]

Step-by-step explanation:

take the base square. find the diagonal

16^2+16^2 = 2*16^2= d^2

d= 16√2

half of the diagonal will form the baSe of right triangle of hypotenuse 10. but the base will be 8√2 which is greater than 10. so I feel the slant hr has to be different and more than 10

6 0
2 years ago
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